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In this theorem we identify that for a specified differential equation a set of fundamental solutions will exist.
Consider the differential equation
y′′ + p (t ) y′ + q (t ) y = 0
Here p(t) and q(t) are continuous functions on any interval I. select t0 to be any point in the interval I. Let y1(t) be a solution to the differential equation which satisfies the initial conditions.
y(t0) = 1
y′ (t0) = 0
Let y2(t) be a solution to the differential equation which satisfies the initial conditions.
y (t0) = 0
y′ (t0) = 1
So y1(t) and y2(t) form a fundamental set of solutions for the differential equation.
This is easy enough to illustrate that these two solutions form a fundamental set of solutions. Just calculate the Wronskian.
Thus, fundamental sets of solutions will exist; we can solve the two IVP's specified in the theorem.
1/a+b+x =1/a+1/b+1/x a+b ≠ 0 Ans: 1/a+b+x =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒ x - ( a + b + x )/ x ( a + b + x ) = + a + b/ ab ⇒
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