The tic-tac-toe program, JAVA Programming

Assignment Help:

Instructions

Modify the program so that the computer will generate moves for the
‘O' player (it must continue to accept user input for ‘X'). A simple way to do this is to use a random value between 0 and 9 to generate moves for ‘O'.

currMove = (int)(Math.random() * 9) + 1;

You will have to ensure, of course, that the computer does not generate a move for a square that is already occupied. Another simple way to generate moves is to simply move to the first unoccupied square.

Also I need explain in words (as clearly and precisely as possible) any improvements you made to the program.

Any other improvement to make this program looks better please sent me in a different attach.

The Program

/**
* Homework Assignment #1 -- Working With Two-Dimensional Arrays (Tic-Tac-Toe)
* CPS , Section [[Put your section number here]]
*
* @author [[Put your name here]]
* @version 1.1 [[Put current date here]]
*/
import java.util.Scanner;

public class Hmwk1 {

public static final char SPACE = ' ';
// Tic-tac-toe board showing move numbers
public static final char[][] MOVE_INFO = {{'1', '2', '3'},
{'4', '5', '6'},
{'7', '8', '9'}};

public static void main(String[] args) {
Scanner in = new Scanner(System.in);

char[][] board = new char[3][3];
char currPlayer = 'X';

fill2D(board, SPACE);
printBoard(MOVE_INFO);
while (!gameOver(board)) {
System.err.print("Move for " + currPlayer + "? ");
int currMove = in.nextInt();
makeMove(currPlayer, currMove, board);
printBoard(board);
currPlayer = nextPlayer(currPlayer);
}
reportResults(board);
}

/**
* Fill a given two-dimensional character array with a given
* character
*
* @param a the array to fill
* @param c the character to use
*/
public static void fill2D(char[][] a, char c) {
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length; j++) {
a[i][j] = c;
}
}
}

public static final String VERT = " * * ";
public static final String HORZ = "***********";

/**
* Print the contents of an array representing a tic-tac-toe
* board
*
* @param board the board configuration to be printed
*/
public static void printBoard(char[][] board) {
System.out.println();
for (int i = 0; i < board.length; i++) {
System.out.println(VERT);
for (int j = 0; j < board[i].length; j++) {
System.out.print(" " + board[i][j] + " ");
if (j < board[i].length - 1) {
System.out.print("*");
} else {
System.out.println();
}
}
System.out.println(VERT);
if (i < board.length - 1) {
System.out.println(HORZ);
}
}
System.out.println();
}

/**
* Determine if the game is over; i.e., if a player has won or if
* there are no more moves possible
*
* @param board current board configuration
* @return true if game is over, false otherwise
*/
public static boolean gameOver(char[][] board) {
return noMovesLeft(board)
|| isWinner('X', board)
|| isWinner('O', board);
}

/**
* Determine if no more moves are possible; i.e., if there
* are no more SPACE's left in the board array
*
* @param board the current board configuration
* @return true if there are no more legal moves, false otherwise
*/
public static boolean noMovesLeft(char[][] board) {
for (int i = 0; i < board.length; i++) {
for (int j = 0; j < board[i].length; j++) {
if (board[i][j] == SPACE) {
return false;
}
}
}
return true;
}

/**
* Determine if a given player is a winner; i.e., has 3 marks in a
* row, either horizontally, vertically, or diagonally
*
* @param player the player to check
* @param board the current board configuration
* @return true if player has 3 marks in a row, false otherwise
*/
public static boolean isWinner(char player, char[][] board) {
// check rows (horizontal)
for (int row = 0; row < 3; row++) {
if (board[row][0] == player && board[row][1] == player
&& board[row][2] == player) {
return true;
}
}
// check cols (vertical)
for (int col = 0; col < 3; col++) {
if (board[0][col] == player && board[1][col] == player
&& board[2][col] == player) {
return true;
}
}
// check diagonals
if (board[0][0] == player && board[1][1] == player
&& board[2][2] == player) {
return true;
} else if (board[0][2] == player && board[1][1] == player
&& board[2][0] == player) {
return true;
} else {
return false;
}
}

/**
* Mark the specified move for the specified player on the given
* board configuration (move == 1 => [0][0], move == 2 => [0][1],
* move == 3 => [0][2], move == 4 => [1][0], move == 5 => [1][1],
* move == 6 => [1][2], move == 7 => [2][0], move == 8 => [2][1],
* move == 9 => [2][2])
*
* @param player the player making the move
* @param move the move to be made
* @param board the current board configuration
*/
public static void makeMove(char player, int move, char[][] board) {
int row = (move - 1) / board.length;
int col = (move - 1) % board[row].length;
board[row][col] = player;
}

/**
* Determine the next player, for cycling X, then O, then X, etc.
*
* @param current the current player ('X' or 'O')
* @return the next player to play ('O' or 'X')
*/
public static char nextPlayer(char current) {
if (current == 'X') {
return 'O';
} else {
return 'X';
}
}

/**
* Report the results of the game, whether X or O won or the game
* ended in a tie.
*
* @param board the board configuration to be described
*/
public static void reportResults(char[][] board) {
if (isWinner('O', board)) {
System.out.println("O is the winner!");
} else if (isWinner('X', board)) {
System.out.println("X is the winner!");
} else {
System.out.println("The game ends in a tie.");
}
}

}


Related Discussions:- The tic-tac-toe program

Please help, Write a program to find the area under the curve y = f(x) betw...

Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b

I want fitlife app for android - ios, I want FitLIFE app for Android, IOS, ...

I want FitLIFE app for Android, IOS, Windows Project Description: Hello, I want to develop an app for Android, IOS and Windows Phone. This app will be work with open source B

Explain about drawing lines, Explain about Drawing Lines? Drawing strai...

Explain about Drawing Lines? Drawing straight lines along with Java is easy. Just call g.drawLine(x1, y1, x2, y2) where (x1, y1) and (x2, y2) are the endpoints of your lines

Explain about core java, Java is increasingly used for middleware applicati...

Java is increasingly used for middleware applications to communicate among Server and clients. Java has features like multithreading, portability and networking capabilities. Chang

Program with fibonacci sequence of first 20 terms, Program 1. Write a J...

Program 1. Write a Java program to display the first 20 Fibonacci numbers Program with Fibonacci sequence of first 20 terms Output 2. Write an applet progr

Extensible messaging and presence protocol, According to XMPP Standards Fou...

According to XMPP Standards Foundation "XMPP is the Extensible Messaging and Presence Protocol, a set of open technologies for instant messaging, presence, multi-party chat, voice

What is an intelligent system, What is an intelligent system? Intellige...

What is an intelligent system? Intelligent system is a SW programs or SW and HW systems designed to perform complex tasks employing strategies in which mimic some aspect of hum

How the jms is different from rpc, In RPC the method invoker waits for the ...

In RPC the method invoker waits for the method to finish implementation and return the control back to the invoker. Therefore it is completely synchronous in nature. Whereas in JMS

Decoding program, 699906626330444777707776662233777 decoding program

699906626330444777707776662233777 decoding program

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd