Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
The Three-phase alternator
In this case, three separate sets of coils are wound on the stator and connected to produce three separate outputs. Because of the physical displacement of the coils around the stator, the outputs will have different phases with respect to each other. Three-phase systems are common even when DC outputs are required (e.g. electric alternators to charge a car battery) because of the torque reaction problem mentioned above. The AC output is rectified with a set of six diodes mounted in a single pack (two diodes are needed to rectify each phase).
A two-pole, three-phase alternator is shown in the diagram below. Stator coils AB belong to phase 1, coils CD to phase 2 and coils EF to phase 3. Each pair of coils are connected in series and their outputs add (e.g. A and B are connected in series to produce phase 1 output). Notice it is two-pole because there are only two poles (i.e. one pole pair) on the rotor. The frequency of each phase output is therefore equal to the rotational speed of the rotor.
Unlike the single-phase alternator, it turns out that the torque required to drive a three-phase alternator is constant, with no pulsating component. This is an important advantage.The figure below shows the arrangement for a multipole three-phase alternator. Again, coils A&B, C&D and E&F are connected in series to three differnet outputs, each with a phase shift of 120° apart (because of the physical arrangement of the coils on the stator).
Circuit with capacitive load Capacitors which obey the relationship of equation are linear capacitors, since the potential difference among the conductive surfaces is linearly
how to design a single phase distribution circuit from a supply point to a load(lights)
Q. For a BJT with vBE = 0.7V, I CBO = 4 nA, i E = 1 mA, and i C = 0.9 mA, evaluate α, iB,iSE, and β.
i v characteristics of practical current source
Q. A dc series motor operates at 750 r/min with a line current of 100 A from the 250-V mains. Its armature-circuit resistance is 0.15 and its series-field resistance is 0.1 . As
why we configure bjt using h parameter model
develop and explain series and parallel magnetic circuits?
Effect of Frequency a.From equation for given H p and μ P v α √f b.From equation the depth of penetration for a given material δ α 1/ √f c.From equation hyst
Q. Some element voltages and currents are given in the network configuration of Figure. Determine the remaining voltages and currents. Also calculate the power delivered to each el
What we have seen for practical power supplies applies to any electrical circuit provided it contains only linear components
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd