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The best algorithm to solve a given problem is one that requires less space in
memory and takes less time to complete its execution. But in practice it is not always possible to achieve both of these objectives. There may be more than one approach to solve a problem. One approach may require more space but less time to complete its execution. The 2nd approach may require less space but takes more time to complete execution. We choose 1st approach if time is a constraint and 2nd approach if space is a constraint. Thus we may have to sacrifice one at cost of the other. That is what we can say that there exists a time space trade among algorithm.
Write the algorithm for compound interest
1. Define the following terms in a rule-based expert system? a) Knowledge base b) Inference engine 2. What is a fuzzy rule? Explain the difference between classical and fuzzy
Let us assume a sparse matrix from storage view point. Assume that the entire sparse matrix is stored. Then, a significant amount of memory that stores the matrix consists of zeroe
The operations of the Symbol ADT The operations of the Symbol ADT are the following. a==b-returns true if and only if symbols a and bare identical. a symbol bin Unico
Ask consider the file name cars.text each line in the file contains information about a car ( year,company,manufacture,model name,type) 1-read the file 2-add each car which is repr
1. Using the traditional method of CPM: a. What activities are on the critical path? b. What is the expected total lead time of the project? 2. Using CCPM: a. What
Suppose that you want to develop a program that accepts a postfix expression and asks values for variables in the expression. Then you need to calculate the answer for the expressi
Data array A has data series from 1,000,000 to 1 with step size 1, which is in perfect decreasing order. Data array B has data series from 1 to 1,000,000, which is in random order.
program on function loading
What are circular queues? Circular queue: Static queues have a very large drawback that once the queue is FULL, even though we erase few elements from the "front" and relieve
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