The maximum amount of ba3(po4)2, Chemistry

Assignment Help:

If 0.5 mol of BaCl2 is mixed with 0.20 mol of Na3PO4, the maximum amount of Ba3(PO4)2 that can be formed is

3 BaCl2 + 2 Na3PO4 = Ba3(PO4)2 + 6NaCl

Here clearly BaCl2 is the limiting agent

So 3 moles of bacl2 gives 1 mole of ba3(po4)2

so 0.5 mole will give 0.2 mole

 


Related Discussions:- The maximum amount of ba3(po4)2

Charles law, a bacterial culture isolsted from sewaga produces36.4cm of met...

a bacterial culture isolsted from sewaga produces36.4cm of methane gas at 27C and 760mmHg this gas occupies 33124cm at 0c and same pressure explainvolume temperature relation ship

Solutions, what volume in milliliters of 12.00M nitric acid (HNO3) stock so...

what volume in milliliters of 12.00M nitric acid (HNO3) stock solution would you us to make 750.0 ml of 3.00M nitric acid solution what volume in milliliters of 12.00M nitric acid

Electrogravimetry, give instrumentation of electrogravimetry

give instrumentation of electrogravimetry

Electromeric effect, types of elecromeric effect and applications

types of elecromeric effect and applications

#physical chemistry, Limitations of second law of thermodynamics

Limitations of second law of thermodynamics

Discuss the ion exchange process of water softening, Discuss the ion exchan...

Discuss the ion exchange process of water softening. Give an account of the variety of mechanisms of Lubrication. Write notes on bulk and solution polymerization techniques.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd