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Show that af+bd+ce=ae+bf+cd= 1/2 , In figure, the incircle of triangle ABC...

In figure, the incircle of triangle ABC touches the sides BC, CA, and AB at D, E, and F respectively. Show that AF+BD+CE=AE+BF+CD= 1/2   (perimeter of triangle ABC), Ans:

.., rectangles 7cm by 4cm

rectangles 7cm by 4cm

Ratios, a muffin recipe calls for three forth of a cup of sugar and one eig...

a muffin recipe calls for three forth of a cup of sugar and one eight of a cup of butter. travis accidentally put in one whole cup of butter. how much sugar does travis need to put

Integration variable, Integration variable : The next topic which we have ...

Integration variable : The next topic which we have to discuss here is the integration variable utilized in the integral. In fact there isn't actually a lot to discuss here other

Determine the quotient and remainder , Let a = 5200 and b = 1320. (a) If...

Let a = 5200 and b = 1320. (a) If a is the dividend and b is the divisor, determine the quotient q and remainder r. (b) Use the Euclidean Algorithm to find gcd(a; b). (c)

An initial species population , An initial species population is y(0) = 300...

An initial species population is y(0) = 3000. At t=0 the population starts to grow exponentially with a doubling time of 2 years. Mark the only correct statement: a)    The per

Compute the volume and surface area of a right circular cone, Compute the v...

Compute the volume and surface area of a right circular cone: Compute the volume and surface area of a right circular cone along with r =  3", h = 4", and l = 5".  Be sure to

Differential Equations, 1.Verify Liouville''s formula for y "-y" - y'' + y ...

1.Verify Liouville''s formula for y "-y" - y'' + y = 0 in (0, 1) ? 2.Find the normalized differential equation which has {x, xex} as its fundamental set. 3.6Find the general soluti

Derive the hicksian demand function using indirect utility , (a) Derive the...

(a) Derive the Marshalian demand functions and the indirect utility function for the following utility function: u(x1, x2, x3) = x1 1/6 x2 1/6 x3 1/6    x1≥ 0, x2≥0,x3≥ 0

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