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Tangent Lines : The first problem which we're going to study is the tangent line problem. Before getting into this problem probably it would be best to define a tangent line.
A tangent line to the function f(x) at the instance x = a is a line which just touches the graph of the function at the point in question & is "parallel" (in some way) to the graph at that point. Consider the graph below.
In this graph the line is a tangent line at the specified point because just it touches the graph at that point and is also "parallel" to the graph at that point. Similarly, at the second point illustrated, the line does just touch the graph at that point, hence it is not "parallel" to the graph at that point & hence it's not a tangent line to the graph at that point.
At the second point illustrated (the point where the line isn't a tangent line) we will sometimes call the line a secant line.
Now, we've used the word parallel a couple of times and we have to probably be a little careful with it. Generally we will think of a line & a graph as being parallel at a point if they are both moving in the same direction at that point. So, in the first point above the graph and the line are moving in the same direction and so we will say they are parallel at that point. At the second point, on the other hand, the line and the graph are not moving in the same direction and so they aren't parallel at that point.
lim n tends to infintiy ( {x} + {2x} + {3x}..... +{nx}/ n2(to the square) )where {X} denotes the fractional part of x? Ans) all no.s are positive or 0. so limit is either positive
Polynomials in two variables Let's take a look at polynomials in two variables. Polynomials in two variables are algebraic expressions containing terms in the form ax n y m
what is the difference between North America''s part of the total population and Africa''s part
Kelly plans to fence in her yard. The Fabulous Fence Company charges $3.25 per foot of fencing and $15.75 an hour for labor. If Kelly requires 350 feet of fencing and the installer
Suppose S = {vi} and T = {ti} are "easy" sets of knapsak weight. Also, P and q are primes p > ?Si and q > ?ti. We can combine S and T into a signle set of knapsack weight as follow
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By the method of completion of squares show that the equation 4x 2 +3x +5 = 0 has no real roots. Ans: 4 x 2 +3 x +5=0 ⇒ x 2 + 3/4 x + 5 = 0 ⇒ x 2 + 3/4 x +
Here we know x can only be 1 or -1. so if it is 1 ans is 2. if x is -1, for n even ans will be 2 if x is -1 and n is odd ans will ne -2. so we can see evenfor negative x also an
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