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SUB: Subtract:- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory location, register or immediate data and the destination operand might be a or a memory location or register, but destination and source operands both might not be memory operands. Destination operand cannot be an immediate data. By this instruction, all the condition code flags are affected. The instance of this instruction along with the addressing modes is followed below:
Example :
1. SUB 0100H Immediate [destination AX]
2. SUB AX, BX Register
3. SUB AX, [5000H] Direct
4. SUB [5000H], 0100 Immediate
write a program that calculates the fibonacci series: except for the first two numbers in the sequence
RET : Return from the Procedure:- At each CALL instruction, the register IP and register CS of the next instruction is pushed to stack, before the control is transferred to the
INT N : Interrupt Type N:- In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed,
I need to generate a random number bby using 8086 assembly language
Example : Write a program to move the contents of the memory location 0500H to BX and also to register CX. Add immediate byte 05H to the data residing in memory location, whose ad
Internal Architecture of Microprocessor : The architecture of 8086 provides a number of improvements over 8085 architecture. It supports a, a set of 16-bit registers ,16-bit AL
Control Transfer or Branching Instruction Control transfer instructions transfer the flow of execution of the program to a new address specified in the instruction indirectly o
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
write an assembly program to display triangular star like shape
As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests
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