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SUB: Subtract:- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory location, register or immediate data and the destination operand might be a or a memory location or register, but destination and source operands both might not be memory operands. Destination operand cannot be an immediate data. By this instruction, all the condition code flags are affected. The instance of this instruction along with the addressing modes is followed below:
Example :
1. SUB 0100H Immediate [destination AX]
2. SUB AX, BX Register
3. SUB AX, [5000H] Direct
4. SUB [5000H], 0100 Immediate
You are to write an assembly language program called subfaq.s that computes the generalized subfactorial function of nonnegative integer inputs i0 and n. The generalized subfactori
MyLocation SDWORD 14 TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebx Show exactly what lives in eax after executi
ADD: Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destinat
assembly language program to find larges number in an array
#I submitted my assignment this morning and it is still processing. How long does it take?
Register Organization of 8086 8086 has a great set of registers containing special purpose and general purpose registers. All the 8086 resisters are 16-bit registers.
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
NOT : Logical Invert: The NOT instruction complements (inverts) the contents of an a memory location or operand register bit by bit. The instance are as following: Example :
Example : Write a program to move the contents of the memory location 0500H to BX and also to register CX. Add immediate byte 05H to the data residing in memory location, whose ad
1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi
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