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Q. Structural steel materials?
All structural steel materials to conform to GS-904-0510.
All miscellaneous steel materials to conform to GS-904-0515.
All welding consumables shall conform to GS-904-0511.
All building products and materials, where applicable, to conform to GS-904-0520.
Surface preparation and painting of structural work to conform to GS-904-0920 and GS-904-0925.
Other civil or structural components of the skid where specified on conceptual drawings shall conform to the relevant section of COLT Engineering specifications.
Skid mounted equipment, piping, vessels, and electrical and instrumentation components shall be in accordance with relevant contract mechanical, piping and electrical specifications.
Joint Details and Preparations Joints shall be prepared by machining, flame cutting with grinding to bright metal or air-carbon arc gouging with grinding to bright metal such t
Compaction This is carried out in several manners that might occupy the addition of a binder or lubricant and application of pressure. Sintering is densification of assembled
T ype s of Loading: Mainly three types of load acts on any beam; 1. Concentrated load ( or point load) 2. Uniformly distributed load 3. Uniformly varying load
limitations of euler''s theory
Reversible and irreversible processes: Thermodynamic system which is capable of restoring the original state of it by reversing the factors responsible for occurrence of proc
The mass flow rate is 28kg/s in an axial flow gas turbine that develops 3.5MW. The stagnation conditions are 780KPa and 730 deg.C. at the entry. At the exit of the nozzle, the stat
Q. Painting of structural components of skid? Sandblasting and priming shall be carried out prior to assembly, and shall include all bolt holes, flange faces, etc. Flange gaske
Determine the number of cycles - crack propagation: The plate of above Example contained a crack of 50 mm length in the centre before it was subjected to cyclic stress. Deter
Q. Explain the terms centre of gravity and centroid. Sol. : A point can be found out in a body through which resultant of all such parallel forces acts. This point through
Prove that the ratio of belt tension is given by the T 1 / T 2 = e μθ Let T1 = Tension in belt on the tight side T2 = Tension in belt on the slack side θ = Angle
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