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String Manipulation Instruction
A series of words or data bytes are available in memory at consecutive locations, to be mention to individually or collectively, are known as byte strings or word strings or byte strings. For instance, a string of characters can be located in consecutive memory locations, where each character can be represented by its ASCII equivalent. For mention to a string, two parameters are needed,
(a) Length of the string and
(b) Starting or ending address of the string.
The length of a string is generally stored as count in the CX register. In case of 8085, same structures may be set up by counter and the pointer arrangements. The counters and pointers can be modified at each iteration until the needed condition for proceeding further is satisfied. Instead, the 8086 supports a set of more powerful instructions for string manipulations. In case of 8086 string instructions, the decrementing or incrementing of the pointer depends on the direction flag (DF) status. If it is a byte string operation then the index registers are updated by one. Instead, if it is a word string operation then the index registers are updated by two. The counter in both of the cases is decremented by one. It consisits of REP, MOVSW/MOVSB, CMPS, SCAS, LODS, STOS.
As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests
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Sum of series of 10 numbers and store result in memory location total
Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register?
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
MOVSW/MOVSB : Move String Word or String Byte: Imagine a string of bytes, stored in a set of consecutive memory locations is to be moved to another set of the destination locati
this is my first project i dont know where to start
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
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