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Prove that bd/cd = bf/ce, In the given figure, ∠AEF=∠AFE and E is the mid-p...

In the given figure, ∠AEF=∠AFE and E is the mid-point of CA. Prove that BD/CD = BF/CE Ans:    Draw CG ¦DF In ΔBDF CG ¦ DF ∴ BD/CD = BF/GF     .............(1)

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If 65% of the populations have black eyes, 25% have brown eyes and the remaining have blue eyes. What is the probability that a person selected at random has (i) Blue eyes (ii) Bro

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If 1/x+2, if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5...

if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5 are in AP find x. 1/x+3 - 1/x+2 = 1/x+5-1/x+3 =>  1/x 2 +5x+6  = 2/ x 2 +8x +15 =>  On solving we get x

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