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Pre-order Traversal
The method of doing a pre-order traversal iteratively then has the several steps(suppose that a stack is available to hold pointers to the appropriate nodes):
1. push NULL onto the stack
2. Begin at the root and begin execution
3. Write the information in the node
4. If the pointer to the right is not NULL push the pointer onto the stack
5. if the pointer to the left is not NULL move the pointer to the node on the left
6. if the pointer to the left is NULL pop the stack
7. repeat steps 3 to 7 until no nodes remain
A linear list of elements in which deletion can be done from one end (front) and insertion can take place only at the other end (rear) is called as a Queue.
A binary tree is a special tree where each non-leaf node can have atmost two child nodes. Most important types of trees which are used to model yes/no, on/off, higher/lower, i.e.,
Given the following search tree, state the order in which the nodes will be searched for breadth first, depth first, hill climbing and best first search, until a solution is reache
Using Assertions When writing code, programmer must state pre- and subtle post conditions for public operations, state class invariants and insert unreachable code assertions a
1) preorder, postorder and inorder 2) The main feature of a Binary Search Tree is that all of the elements whose values is less than the root reside into the nodes of left subtr
AVL tree An AVL tree is a binary search tree in which the height of the left and right subtree of the root vary by at most 1 and in which the left and right subtrees are again
The searching technique that takes O (1) time to find a data is Hashing is used to find a data
Q. Describe the adjacency matrix and make the same for the given undirected graph. Ans: The representation of Adjacency Matrix: This representation consists of
We will start by defining a new structure called Heap. Figure 3 illustrates a Binary tree. Figure: A Binary Tree A complete binary tree is said to assure the 'heap con
* Initialise d & pi* for each vertex v within V( g ) g.d[v] := infinity g.pi[v] := nil g.d[s] := 0; * Set S to empty * S := { 0 } Q := V(g) * While (V-S)
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