Steam power plant , Mechanical Engineering

Assignment Help:

Steam power plant:

Steam power plant converts heat energy Q from combustion of fuel into mechanical work W of shaft rotation which is used to generate electricity. This type plant operates on thermodynamic cycle in closed loop of processes following one another such that working fluid of steam and water repeats the cycles continuously. If first law of thermodynamics is applied to thermodynamic cycle in which working fluid returns to the initial condition of it, the energy flowing into fluid at the time of cycle should be equal to that flowing out of cycle.

Qin + Win = Qout + Wout Or,    Qin  - Qout = Wout - Win Where;

Q = Rate of Heat transfer

W = Rate of work transfer, that is power

Heat and work are mutually convertible. However, quantity of work energy can be converted into heat energy, the converse is not true. A quantity of heat cannot be converted into work.

Heat flows because of temperature difference, and this means that in order to flow, two heat reservoirs should be present; a hot source and a cold sink. During heat flow from the hot source to cold sink, a fraction of flow can be converted into work energy, and function of power plant is to generate this conversion. However, some heat should flow into the cold sink because of its presence. Thus rate of heat transfer Qout of the cycle should always be positive and the efficiency of conversion of heat energy into work energy can never be 100 percent at all. Thermodynamic efficiency for the cycle, nth is the measure of how well cycle converts heat into work.

1809_Steam power plant.png


Related Discussions:- Steam power plant

Bodies stick together after collision the heat liberated, Two bodies of mas...

Two bodies of mass 1 kg and 2 kg move towards each other in mutually perpendicular direction with velocities 3m/s and 2 m/s respectively. If the bodies stick together after collisi

EM13939497, Do the answers come with the full calculations?

Do the answers come with the full calculations?

Cobalt-base super alloys, Cobalt-base super alloys (e.g. UNS R30155 (Grade ...

Cobalt-base super alloys (e.g. UNS R30155 (Grade 661) and R30816 (Grade 671)) have superior strength to the nickel base alloys above 1800°F (980°C). The refractory metal alloys

Explain working of belt transmission type dynamometer, Explain construction...

Explain construction and working of Belt transmission type Dynamometer?

Determine the steady state amplitude of vibration, 1. (a) Sketch frequency-...

1. (a) Sketch frequency-response curves for a damped single degree of freedom system subjected to a harmonic excitation under three different damping ratios. The system has a natur

Involutes, considerations for shape changers

considerations for shape changers

Evaluate the temperature of the centre of the bar, A copper bar 80 mm by 60...

A copper bar 80 mm by 60 mm in cross-section (k = 370 W/m ºC) is lying in a insulated trough so that the heat transfer from one face both the edges is negligible. It is seen that w

Short life cycle demand uncertainty - risk management, how I can formulate ...

how I can formulate mathematically the risk management in demand uncertainty of short life cycle product.

Closed, Closed, open and isolated system-Thermodynamics system: Sol: ...

Closed, open and isolated system-Thermodynamics system: Sol: In thermodynamics the system can be defined as the quantity of matter or region in space upon which attention is

Where pneumatic system is used, Any system needs redundancy in work needs p...

Any system needs redundancy in work needs pneumatics, because the compressor of the pneumatic system has periodical operations (intermittent work, not as hydraulic pump). The compr

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd