Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Static Data Members:
A data member inside the class can construct as static data member. There are few
guidelines to be followed when declaring static data member.
The following program will give clear difference between static data count and regular data number members. The static data is common to all objects but regular data is unique to its object.
class item
{int number; static int count; public:
void getdata()
{++count;
number=count;
}
void putdata(void)
{cout<<"Count is "< cout<<"Number is "< } }; int item::count=0; int main() { clrscr(); item x,y,z; //Three object produced from class item x.getdata(); y.getdata(); z.getdata(); x.putdata(); The count is 3 and number is 1 y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3 return 0; } Static Member Function: The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function. Rules of Static Member function are given below: The static member function can read static data member only from its class. The static member function is called using class name not object name. class_name::static_function_name( ); It can also be called using object.static_fun( ). The given program will illustrate how the static member function is worked. class find {static int count; int code; public: static void showcount(void) {cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
cout<<"Number is "< } }; int item::count=0; int main() { clrscr(); item x,y,z; //Three object produced from class item x.getdata(); y.getdata(); z.getdata(); x.putdata(); The count is 3 and number is 1 y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3 return 0; } Static Member Function: The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function. Rules of Static Member function are given below: The static member function can read static data member only from its class. The static member function is called using class name not object name. class_name::static_function_name( ); It can also be called using object.static_fun( ). The given program will illustrate how the static member function is worked. class find {static int count; int code; public: static void showcount(void) {cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
};
int item::count=0;
int main()
{ clrscr();
item x,y,z; //Three object produced from class item x.getdata();
y.getdata();
z.getdata();
x.putdata(); The count is 3 and number is 1
y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3
return 0;
Static Member Function:
The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function.
Rules of Static Member function are given below:
The given program will illustrate how the static member function is worked.
class find
{static int count;
int code;
public:
static void showcount(void)
{cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
void setcode(void)
{code = ++count;
void setcount(void)
{ cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
} }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
int find ::count=0;
{clrscr();
find x,y,z;
x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2
z.setcode(); //Code and count is 3 find::showcount(); //Count is 3
x.setcount(); // Code is 1 for object x.
y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z.
x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6
//The value of code will increase from its previous value of that object.
x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x.
Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
Write a c program to determine interchanged values between two variables?[Hint - if loop] What will be the output of the program? How many times this loop will execute? Wr
F u nction overloading: Functions can be defined with same name. Depending upon the type of argument passed the function will perform. This is known function overloading
why c++
O v e r l o a d i n g U n a r y Op e r a t o r s Us i n g F r i e n d F u n c t i o n cl a ss s i g n { i n t a ,
what is the syntax to get a coloured output.
i need expression and its types with example programs in c++
In general, Roman numerals can be converted mathematically by simply assigning a numerical value to each letter, according to the chart below, and calculating a total: M=1000 | D=5
Given an integer n and a permutation of numbers 1, 2 ... , n-1, n write a program to print the permutation that lexicographically precedes the given input permutation. If the given
Define Functions with arguments and no return values The calling function will read a data from the terminal and pass it on to called as function and this will work good as the
Jewels can only be removed for polishing from either end of the necklace
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd