Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Static Data Members:
A data member inside the class can construct as static data member. There are few
guidelines to be followed when declaring static data member.
The following program will give clear difference between static data count and regular data number members. The static data is common to all objects but regular data is unique to its object.
class item
{int number; static int count; public:
void getdata()
{++count;
number=count;
}
void putdata(void)
{cout<<"Count is "< cout<<"Number is "< } }; int item::count=0; int main() { clrscr(); item x,y,z; //Three object produced from class item x.getdata(); y.getdata(); z.getdata(); x.putdata(); The count is 3 and number is 1 y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3 return 0; } Static Member Function: The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function. Rules of Static Member function are given below: The static member function can read static data member only from its class. The static member function is called using class name not object name. class_name::static_function_name( ); It can also be called using object.static_fun( ). The given program will illustrate how the static member function is worked. class find {static int count; int code; public: static void showcount(void) {cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
cout<<"Number is "< } }; int item::count=0; int main() { clrscr(); item x,y,z; //Three object produced from class item x.getdata(); y.getdata(); z.getdata(); x.putdata(); The count is 3 and number is 1 y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3 return 0; } Static Member Function: The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function. Rules of Static Member function are given below: The static member function can read static data member only from its class. The static member function is called using class name not object name. class_name::static_function_name( ); It can also be called using object.static_fun( ). The given program will illustrate how the static member function is worked. class find {static int count; int code; public: static void showcount(void) {cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
};
int item::count=0;
int main()
{ clrscr();
item x,y,z; //Three object produced from class item x.getdata();
y.getdata();
z.getdata();
x.putdata(); The count is 3 and number is 1
y.putdata(); The count is 3 and number is 2 z.putdata(); The count is 3 and number is 3
return 0;
Static Member Function:
The static member function can be specified like static data member. It works asc a static member data except the static member data is used in static member function.
Rules of Static Member function are given below:
The given program will illustrate how the static member function is worked.
class find
{static int count;
int code;
public:
static void showcount(void)
{cout<<"Count is " < } void setcode(void) {code = ++count; } void setcount(void) { cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
void setcode(void)
{code = ++count;
void setcount(void)
{ cout<<"Code is " < } }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
} }; int find ::count=0; int main() {clrscr(); find x,y,z; x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2 z.setcode(); //Code and count is 3 find::showcount(); //Count is 3 x.setcount(); // Code is 1 for object x. y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z. x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6 //The value of code will increase from its previous value of that object. x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x. return 0; } Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
int find ::count=0;
{clrscr();
find x,y,z;
x.setcode(); // Code and count is 1. y.setcode(); //Code and count is 2 find::showcount(); //Count is 2
z.setcode(); //Code and count is 3 find::showcount(); //Count is 3
x.setcount(); // Code is 1 for object x.
y.setcount(); // Code is 2 for object y. z.setcount(); // Code is 3 for object z.
x.setcode(); // Code and count is 4. y.setcode(); //Code and count is 5 z.setcode(); //Code and count is 6 find::showcount(); //Count is 6
//The value of code will increase from its previous value of that object.
x.setcount(); // Code is 4 for object x. y.setcount(); / Code is 5 for object x. z.setcount(); // Code is 6 for object x.
Since the count is declared as static it has only one copy irrespective of number of objects created. When static count function called again and again it will increase count for all the objects created simultaneously therefore the count will be uniform for all object, but for the data member code it is unique for each object created because it is not a static data member. Therfore from the above example there will only one value for count data member irrespective of number of objects constructed since it is a static data member, where as for code data member the value will be different for each object.
I need help with a c# program. Do yall help with c sharp
A body which has three forces acting on it is in equilibrium. One force is 3N to the North and the other is 4N to the west. What us the magnitude and direction of the third force?
Simple program of c++: int main() { int bushels; float dollars, rate; cout cin >> dollars; cout
I need help to understand and do this assignment ********************************************************* You are to insert the missing code in the C program given for combinatio
sample of program that use in bubble sort using assignment operator in c++
What is memory allocation? Memory Allocation : It is the method of allocating memory storage to program in such that the program can be run.
Create an applet that bounces a blue ball inside an applet using Thread. The ball (diameter is 10) will start at position (0,0). When the ball hits the edge of the applet, the ba
Please give me a programming code of first & follow with c or c++ laqnguage .When anyone give me the programming code of first & follow please explain every lines with the help
answer for tcs is working question
#questio#A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concate
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd