Starting methods for polyphase induction motors, Electrical Engineering

Assignment Help:

Starting Methods for Polyphase Induction Motors

When high starting torques are required, a wound-rotor induction motor, with external resistances inserted in its rotor circuits, can be used. The starting current can be reduced and high values of starting torque per ampere of starting current can be obtained with rotor-resistance starting. The external resistances are generally cut out in steps as the machine runs up to speed.

For squirrel-cage-rotor machines, the problem is to keep down the starting current while maintaining adequate starting torque. The input current, for example, can be no more than 6 times the full-load current,while the starting torquemay be about 1.5 times the full-load torque.Depending on the capacity of the available supply system, direct-on-line starting may be suitable only for relatively small machines, up to 10-hp rating. Other starting methods include reduced-voltage starting by means of wye-delta starting, autotransformer starting, or stator-impedance starting.

883_Starting Methods for Polyphase Induction Motors.png

For employing the wye-delta starting method, a machine designed for delta operation is connected in wye during the starting period. Because the impedance between line terminals for wye connection is three times that for delta connection for the same line voltage, the line current at standstill for wye connection is reduced to one-third of the value for delta connection. Since the phase voltage is reduced by a factor of √3 during starting, it follows that the starting torque will be one-third of normal. For autotransformer starting, the setting of the autotransformer can be predetermined to limit the starting current to any desired value.An autotransformer,which reduces the voltage applied to the motor to x times the normal voltage, will reduce the starting current in the supply system as well as the starting torque of the motor to x2 times the normal values.

Stator-impedance starting may be employed if the starting-torque requirement is not severe. Series resistances (or impedances) are inserted in the lines to limit the starting current. These resistances are short-circuited out when the motor gains speed. This method has the obvious disadvantage of inefficiency caused by the extra losses in the external resistances.


Related Discussions:- Starting methods for polyphase induction motors

Which alloy is used for making heater & thermocouple element, Give the name...

Give the names of four alloys along with their composition, which are used for making heater and thermocouple elements. Constantan or Eureka {(55 to 60 percent) Cu, (45 to 40 p

Motor, What is the main function of the slip ring

What is the main function of the slip ring

Explain thevenin''s theorem procedure, Thevenin's theorem procedure:   1. ...

Thevenin's theorem procedure:   1.  Open circuit R L and find Thevenin's voltage (V TH ). 2.  Find Thevenin's resistance (R TH ) when voltage source is short circuit or curren

Determine the bits required for a d/a converter, Q. Determine the bits requ...

Q. Determine the bits required for a D/A converter to detect 1-V change when V ref = 15 V.

Different types of probes used in cathode ray oscilloscope, Q.   Explain th...

Q.   Explain the different types of probes used in cathode Ray Oscilloscope (CRO). Sol. probes: The probe performs the very important function of connecting the test circuit

Calculate the actual frequency of circuit, (a) The circuit of Figure 1 repr...

(a) The circuit of Figure 1 represents an amplifier-speaker connection. The filter is a low pass filter which is connected to the woofer. The filter is a -network. (i) Design a

Give some applications of german silver, Give some applications of German s...

Give some applications of German silver. German silver is an alloy of zinc, nickel and copper. German silver is used in electrical measuring instruments.

Transformers, A 15kVA has a turns ratio 1:10. If the voltage applied is 13....

A 15kVA has a turns ratio 1:10. If the voltage applied is 13.8kV and the applied load is 20+j6. Find the current in the secondary winding and the active and reactive power consumed

Weighted-resistor converter, Q. WEIGHTED-RESISTOR CONVERTER? Figure sho...

Q. WEIGHTED-RESISTOR CONVERTER? Figure shows a 4-bit weighted-resistor D/A converter which includes a reference voltage source, a set of four electronically controlled switches

Function generator, explain the waorking principle of function generator

explain the waorking principle of function generator

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd