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Standardizing Normal Variables
Suppose we have a normal population. We can represent it by a normal variable X. Further, we can convert any value of X into a corresponding value Z of the standard normal variable, by using the formula
Where,
X = the value of any random variable
m = the mean of the distribution of the random variable
s = the standard deviation of the distribution
Z = the number of standard deviations from X to the mean of the distribution and is known as the Z score or standard score.
1+1
Solve the subsequent IVP and find the interval of validity for the solution xyy' + 4x 2 + y 2 = 0, y(2) = -7, x > 0 Solution: Let's first divide on both
We know that the terms in G.P. are: a, ar, ar 2 , ar 3 , ar 4 , ................, ar n-1 Let s be the sum of these terms, then s = a + ar + ar 2
use the simplex method to solve the following lp problem. max z = 107x1 + x2 + 2x3 subject to 14x1 + x2 - 6x3 + 3x4 = 7 16x1 + x2 - 6x3 3x1 - x2 - x3 x1,x2,x3,x4 > = 0
In class 1, the teacher had written down the digits 0,1, ...., 9 on the board. Then she made all the children recite the corresponding number names. Finally, she made them write th
if oranges are bought at the rate of 11 for rupees 10 and are sold at the rate of 10 for rupees 11, find the profit percent
5289441+4684612131
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Solve the subsequent IVP Y'' - 9 y = 0, y(0) = 2, y'(0) = -1 Solution First, the two functions y (t ) = e 3t and y(t ) = e -3t That is "nice enough" for us to
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