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Q. Describe Standard Normal Distribution?
Ans.
The Standard Normal Distribution has a mean of 0 and a standard deviation of 1. The letter Z is often used to refer to a standard normal random variable.
Note that, although many applications in the real world have a normal distribution, rarely does anything in the real world follow a standard normal distribution. This is a convenient distribution that can be used (after some transformations) for ANY normal distribution. In the following examples, we will work through finding probabilities for a standard normal random variable.
Click here to see a table with probabilities for the standard normal distribution.
The area under the curve, the shaded area in this diagram, represents the probability of a normally distributed random variable obtaining a value less than z,.
The entries in the table are the probabilities that a random variable having the standard normal distribution assumes a value less than z.
The vector a → =(2,4) compute 3a → , ½ a → and -2a → . Graph all four vectors on similar axis system. Solution: Now here are the three scalar Multiplication 3a → = (6,
without a calculator give the exact value of each of the following logarithms. (a) (b) log1000 (c) log 16 16 (d) log 23 1 (e) Solution (b) log10
project
square root 2 on the number line
If you have 60% alcohol and wish to dilute with water to make 12 liters 40% alcohol, How many liters of water should you add?
Area between Two Curves We'll start with the formula for finding the area among y = f(x) and y = g(x) on the interval [a,b]. We will also suppose that f(x) ≥ g(x) on [a,b].
If z=re i ? ,find the value of |e iz | Solution) z=r(cos1+isin1) |e iz |=|e ir(cos1+isin1) |=|e -rsin1 |=e -rsin1
please i need the solution for halm''s differential equation
Multiply following. (a) (4x 2 -x)(6-3x) (b) (2x+6) 2 Solution (a) (4x 2 - x )(6 - 3x ) Again we will only FOIL this one out. (4x 2 - x )(6 - 3x) = 24x 2 -
ABC is a right triangle right-angled at C and AC=√3 BC. Prove that ∠ABC=60 o . Ans: Tan B = AC/BC Tan B = √3 BC/BC Tan B =√3 ⇒ Tan B = Tan 60 ⇒ B = 60
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