Stacks, Data Structure & Algorithms

Assignment Help:

Q. Explain what are the stacks? How can we use the stacks  to check whether an expression is correctly parentheses or not. For example (()) is well formed but (() or )()( is not well formed.

 

Ans:

The stack is a data structure that organizes data in a similar way one organizes a pile of coins. The new coin is all the time placed on the top and the oldest is on the bottom of the stack. When we are accessing coins, the last coin on the pile is the first coin which was removed from the stack. If we want to reach the third coin, we should remove the first two coins from the top of the stack first so that the third coin comes on the top of the stack and we can easily remove it. There is no way at all to remove a coin from anywhere other than the top of the stack.

A stack is useful whenever we need to store data and retrieve data in last in, first out order. Let us take an example the computer processes instructions using a stack in which the next instruction to execute is at the top of the stack.

To determine whether an expression is well parentheses or not:- the two conditions should be fulfilled while pushing an expression into a stack. At first, whenever an opening bracket is pushed inside a stack, there should be an occurrence a closing bracket before we reach the last symbol. Whenever a closing bracket is encountered, the top of the stack is popped until the opening bracket is popped out and discarded. If no such type of opening bracket is found and stack is made empty, then this means that the expression is not well parentheses designed.

An algorithm to check that whether an expression is correctly parenthized or not is written below:

flag=TRUE;

clear the stack;

Read a symbol from input string;

while not end of input string and flag do

{

if(symbol= '( ' or symbol= '[' or symbol = '{' )

push(symbol,stack);

else  if(symbol= ') ' or symbol= '[' or symbol =

'{' )

if stack is empty flag=false;

printf("More right parenthesis than left

parenthises");

else c=pop(stack);

match c and the input symbol; If not matched

{     flag=false;

printf("Mismatched

parenthesis");

}

Read the next input symbol;

}

if stack is empty then

printf("parentheses are balanced properly");

else

printf(" More number of left parentheses than right parentheses");

 


Related Discussions:- Stacks

Efficient way of storing a sparse matrix in memory, Explain an efficient wa...

Explain an efficient way of storing a sparse matrix in memory.   A matrix in which number of zero entries are much higher than the number of non zero entries is called sparse mat

Explain first - fit method, First - Fit Method: -    The free list is trave...

First - Fit Method: -    The free list is traversed sequentially to search the 1st free block whose size is larger than or equal to the amount requested. Once the block is found it

Calculate address of an element in an array., Q. Explain the technique to c...

Q. Explain the technique to calculate the address of an element in an array. A  25 × 4  matrix array DATA is stored in memory in 'row-major order'. If base  address is 200 and

Example of pre order traversal, Example of pre order traversal: Reading of...

Example of pre order traversal: Reading of a book, since we do not read next chapter unless we complete all sections of previous chapter & all its sections. Figure  : Rea

Deletion of any element from the queue, Program segment for the deletion of...

Program segment for the deletion of any element from the queue delmq(i)  /* Delete any element from queue i */ { int i,x; if ( front[i] == rear[i]) printf("Queue is

Rooted tree, It does not have any cycles (circuits, or closed paths), which...

It does not have any cycles (circuits, or closed paths), which would imply the existence of more than one path among two nodes. It is the most general kind of tree, and might be co

Advantage of list over arrays, The advantage of list over Arrays is flexibi...

The advantage of list over Arrays is flexibility. Over flood is not a problem until the computer memory is bushed. When the individual record are quite large, it may be difficult t

Division-remainder hashing, According to this, key value is divided by any ...

According to this, key value is divided by any fitting number, generally a prime number, and the division of remainder is utilized as the address for the record. The choice of s

Binary search, Explain binary search with an example

Explain binary search with an example

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd