Stacks, Data Structure & Algorithms

Assignment Help:

Q. Explain what are the stacks? How can we use the stacks  to check whether an expression is correctly parentheses or not. For example (()) is well formed but (() or )()( is not well formed.

 

Ans:

The stack is a data structure that organizes data in a similar way one organizes a pile of coins. The new coin is all the time placed on the top and the oldest is on the bottom of the stack. When we are accessing coins, the last coin on the pile is the first coin which was removed from the stack. If we want to reach the third coin, we should remove the first two coins from the top of the stack first so that the third coin comes on the top of the stack and we can easily remove it. There is no way at all to remove a coin from anywhere other than the top of the stack.

A stack is useful whenever we need to store data and retrieve data in last in, first out order. Let us take an example the computer processes instructions using a stack in which the next instruction to execute is at the top of the stack.

To determine whether an expression is well parentheses or not:- the two conditions should be fulfilled while pushing an expression into a stack. At first, whenever an opening bracket is pushed inside a stack, there should be an occurrence a closing bracket before we reach the last symbol. Whenever a closing bracket is encountered, the top of the stack is popped until the opening bracket is popped out and discarded. If no such type of opening bracket is found and stack is made empty, then this means that the expression is not well parentheses designed.

An algorithm to check that whether an expression is correctly parenthized or not is written below:

flag=TRUE;

clear the stack;

Read a symbol from input string;

while not end of input string and flag do

{

if(symbol= '( ' or symbol= '[' or symbol = '{' )

push(symbol,stack);

else  if(symbol= ') ' or symbol= '[' or symbol =

'{' )

if stack is empty flag=false;

printf("More right parenthesis than left

parenthises");

else c=pop(stack);

match c and the input symbol; If not matched

{     flag=false;

printf("Mismatched

parenthesis");

}

Read the next input symbol;

}

if stack is empty then

printf("parentheses are balanced properly");

else

printf(" More number of left parentheses than right parentheses");

 


Related Discussions:- Stacks

Simulation of queues, Simulation of queues: Simulation is the process of f...

Simulation of queues: Simulation is the process of forming an abstract model of a real world situation in order to understand the effect of modifications and the effect of introdu

Pre-order and post order traversal of a binary tree, The pre-order and post...

The pre-order and post order traversal of a Binary Tree generates the same output. The tree can have maximum One node

Recursive function , Q. Write down the recursive function to count the numb...

Q. Write down the recursive function to count the number of the nodes in the binary tree.    A n s . R ecursive Function to count no. of Nodes in Binary Tree is writt

Operations on sequential files, Insertion: Records has to be inserted at t...

Insertion: Records has to be inserted at the place dictated by the sequence of keys. As is obvious, direct insertions into the main data file would lead to frequent rebuilding of

DAA, what do we use asymptotic notation in study of algorithm?Describe vari...

what do we use asymptotic notation in study of algorithm?Describe various asymptotic notation and give their significance.

Total impedent of the circuit, an electrical student designed a circuit in...

an electrical student designed a circuit in which the impedence in one part of a series circuit is 2+j8 ohms and the impedent is another part of the circuit is 4-j60 ohm mm program

#titlestrings, given the string "Data Structures & , Algorithms", write a p...

given the string "Data Structures & , Algorithms", write a program that uses sequential search to return index of ''&''

Best case, for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a...

for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a[k]=a[j]+i else if a[1]>4 && a[1] for 2 to a[1] a[j]= a{j]+5 else for 2to n a[j]=a[j]+i ..

Threaded binary tree, i need the full concept of it... please can anyone pr...

i need the full concept of it... please can anyone provide

Deletion from a red-black tree, Deletion in a RBT uses two main processes, ...

Deletion in a RBT uses two main processes, namely, Procedure 1: This is utilized to delete an element in a given Red-Black Tree. It involves the method of deletion utilized in

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd