Stacks, Data Structure & Algorithms

Assignment Help:

Q. Explain what are the stacks? How can we use the stacks  to check whether an expression is correctly parentheses or not. For example (()) is well formed but (() or )()( is not well formed.

 

Ans:

The stack is a data structure that organizes data in a similar way one organizes a pile of coins. The new coin is all the time placed on the top and the oldest is on the bottom of the stack. When we are accessing coins, the last coin on the pile is the first coin which was removed from the stack. If we want to reach the third coin, we should remove the first two coins from the top of the stack first so that the third coin comes on the top of the stack and we can easily remove it. There is no way at all to remove a coin from anywhere other than the top of the stack.

A stack is useful whenever we need to store data and retrieve data in last in, first out order. Let us take an example the computer processes instructions using a stack in which the next instruction to execute is at the top of the stack.

To determine whether an expression is well parentheses or not:- the two conditions should be fulfilled while pushing an expression into a stack. At first, whenever an opening bracket is pushed inside a stack, there should be an occurrence a closing bracket before we reach the last symbol. Whenever a closing bracket is encountered, the top of the stack is popped until the opening bracket is popped out and discarded. If no such type of opening bracket is found and stack is made empty, then this means that the expression is not well parentheses designed.

An algorithm to check that whether an expression is correctly parenthized or not is written below:

flag=TRUE;

clear the stack;

Read a symbol from input string;

while not end of input string and flag do

{

if(symbol= '( ' or symbol= '[' or symbol = '{' )

push(symbol,stack);

else  if(symbol= ') ' or symbol= '[' or symbol =

'{' )

if stack is empty flag=false;

printf("More right parenthesis than left

parenthises");

else c=pop(stack);

match c and the input symbol; If not matched

{     flag=false;

printf("Mismatched

parenthesis");

}

Read the next input symbol;

}

if stack is empty then

printf("parentheses are balanced properly");

else

printf(" More number of left parentheses than right parentheses");

 


Related Discussions:- Stacks

How to write binary search algorithm?, Q. Write down the binary search algo...

Q. Write down the binary search algorithm and trace to search element 91 in following given list: 13          30          62           73         81         88             91

An undirected graph g with n vertices and e edges, An undirected graph G wi...

An undirected graph G with n vertices and e edges is shown by adjacency list.  What is the time required to generate all the connected components? O (e+n)

User-specified memory location, You need to implement a function which will...

You need to implement a function which will write out a given user-specified memory location to disk in base 10. That means that you have to convert the large number data structure

Explain the array and linked list implementation of stack, Question 1. ...

Question 1. How can you find out the end of a String? Write an algorithm to find out the substring of a string. 2. Explain the insertion and deletion operation of linked lis

Algorithm to merge two sorted arrays with third array, Q. Write down an alg...

Q. Write down an algorithm to merge the two sorted arrays into the third array. Do  not perform the sort function in the third array.                           Ans: void m

Algorithms for push and pop operation, Q. Suggest a method of implementing ...

Q. Suggest a method of implementing two stacks in one array such that as long as space is there in an array, you should be capable to add an element in either stack. Using proposed

Explain the interfaces in ruby, Explain the Interfaces in Ruby Recall...

Explain the Interfaces in Ruby Recall that in object-oriented programming, an interface is a collection of abstract operations that cannot be instantiated. Even though Ruby i

Preorder - postorder and inorder, 1) preorder, postorder and inorder 2) ...

1) preorder, postorder and inorder 2) The main feature of a Binary Search Tree is that all of the elements whose values is less than the root reside into the nodes of left subtr

In order post order, illlustraate the construction of tree of a binary tree...

illlustraate the construction of tree of a binary tree given its in order and post order transversal

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd