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The square of one integer is 55 less than the square of the next consecutive integer. Find the lesser integer.
Let x = the lesser integer and let x + 1 = the greater integer. The sentence, "The square of one integer is 55 less than the square of the further consecutive integer," can translate to the equation x2 = (x + 1)2 -55. Multiply the binomial (x + 1)2 as (x + 1)(x + 1) by using the distributive property: x2 = x2 + 1x + 1x + 1 - 55. Combine such as terms: x2 = x2 + 2x - 54. Subtract x2 from both sides of the equation: x2 - x2 = x2 - x2 + 2x - 54. Add 54 to both sides of the equation: 0 + 54 = 2x - 54 + 54. Divide both sides through 2: 54/2 = 2x/2. The variable is now alone: 27 = x. The lesser integer is 27.
Since we are going to be working almost exclusively along with systems of equations wherein the number of unknowns equals the number of equations we will confine our review to thes
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