Spurious correlations, Mathematics

Assignment Help:

Spurious Correlations

- in several rare situations when plotting the data for x and y we may have a group indicating either positive correlation or negative (-ve) correlation but when you analyze the data for x and y in general life there may be no convincing evidence that there is such a relationship. Therefore this shows that the relationship only exists in theory and thus it is referred to as spurious or non sense for illustration, when high pass rates of student show high relation along with increased accidents.

 


Related Discussions:- Spurious correlations

Calc, How to find a function

How to find a function

Break even point, what is break even point and how can it helps managers to...

what is break even point and how can it helps managers to make decisions?

Application of derivatives, the base b of a triangle increases at the rate ...

the base b of a triangle increases at the rate of 2cm per second, and height h decreases at the rate of 1/2 cm per second. Find rate of change of its area when the base and height

Distance traveled by car - word problem, Distance Traveled by Car - word pr...

Distance Traveled by Car - word problem: It takes a man 4 hours to reach a destination 1325 miles from his home. He drives to the airport at an average speed of 50 miles per h

., There are k baskets and n balls. The balls are put into the baskets rand...

There are k baskets and n balls. The balls are put into the baskets randomly. If k

Estimate the total cost of the books, Frederick bought six books which cost...

Frederick bought six books which cost d dollars each. What is the total cost of the books? Frederick would multiply the number of books, 6, through how much each one costs, d.

What are the properties of normal distribution, What are the properties of ...

What are the properties of Normal distribution? The normal curve is symmetrical when p=q or p≈q The normal curve is a single peaked curve The normal curve is asymptotic t

BOUNDARY VALUE PROBLEM, Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0...

Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd