Solving equations by completing the square method, Mathematics

Assignment Help:

I need help for Solving Equations by Completing the Square Method, can anybody help me out for this?

Related Discussions:- Solving equations by completing the square method

Trigonometry, 1-tan^2 A/1+tan^2 = cos A - sinA/cos A

1-tan^2 A/1+tan^2 = cos A - sinA/cos A

Factoring quadratic polynomials, Primary, note that quadratic is another te...

Primary, note that quadratic is another term for second degree polynomial. Thus we know that the largest exponent into a quadratic polynomial will be a2. In these problems we will

Math.., how many sixs are in 60

how many sixs are in 60

LASPEYRES AND PAASCHE, advantages and disadvantages of laspeyres and paasch...

advantages and disadvantages of laspeyres and paasche

Word problem in algebra, robin runs 5 kilometers around the campus in the s...

robin runs 5 kilometers around the campus in the same length of time as he can walk 3 kilometers from his house to school. If he runs 4 kilometers per hour faster than he walks, ho

Derivative by frist principal, cosx

cosx

Math 533, Project part A, part B, part C

Project part A, part B, part C

Solve the inequality |x - 1| + |x - 2|, Solve the inequality |x - 1| + |x -...

Solve the inequality |x - 1| + |x - 2|≤ 3. Working Rule: First of all measure the expression to zero whose modulus happens in the given inequation and from this search the va

Y=Theea[sin(inTheeta)+cos(inTheeta)], Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷d...

Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution) Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SI

Polygon on a coordinate, a square tile measures 12 inches by 12 inches each...

a square tile measures 12 inches by 12 inches each unit on a coordinate grid represents 1 inch (1,1) and (1,13) are two of the coordinate of the tile drawn on the grid what are the

Jack 2/12/2013 2:31:28 AM example, Solve by completing the square. i. 3x² = 9x ii. 2x² + 3x + 1 = 0 Solutions i. 3x² = 9x or (3x² - 9x = 0) x² - 3x = 0 (Step 1) x² - 3x + (-(3/2)²) = -(3/2)² (Step 2) x(-(3/2)²)= 9/4 (Step 3) x -3 = + √(9/4) (step 4) (∴ x = (3/2) + (3/2)) = (3+3)/2 or (3/2) - (3/2) = (= 3 or 0) ii) 2x² + 3x + 1 = 0 or (2x² + 3x = -1) X² + (3x/2) = -(1/2) (step 1) X² + (3x/2) + (3/4)²= (3/4)² - 1/2 (step 2) (x +(3/4)²) = 1/16 (step 3) X + (3/4) = + √(1/16) X = - (3/4) = + (1/4) -(3/4) + (1/4) or -(3/4)-(1/4) X = -(1/2) or x = -1

Jack

2/12/2013 2:31:28 AM

example,

Solve by completing the square.

i. 3x² = 9x

ii. 2x² + 3x + 1 = 0

Solutions

i. 3x² = 9x or

(3x² - 9x = 0)

x² - 3x = 0 (Step 1)

x² - 3x + (-(3/2)²) = -(3/2)² (Step 2)

x(-(3/2)²)= 9/4 (Step 3)

x -3 = + √(9/4) (step 4)

(∴ x = (3/2) + (3/2))

= (3+3)/2 or (3/2) - (3/2) =

(= 3 or 0)

ii) 2x² + 3x + 1 = 0 or (2x² + 3x = -1)

X² + (3x/2) = -(1/2) (step 1)

X² + (3x/2) + (3/4)²= (3/4)² - 1/2 (step 2)

(x +(3/4)²) = 1/16 (step 3)

X + (3/4) = + √(1/16)

X = - (3/4) = + (1/4)

-(3/4) + (1/4) or -(3/4)-(1/4)

X = -(1/2) or x = -1

Write Your Message!

Name

Email id

Message

Verfication Code

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

Submit Assignment

User Account

All Pages