Solving equations by completing the square method, Mathematics

Assignment Help:

I need help for Solving Equations by Completing the Square Method, can anybody help me out for this?

Related Discussions:- Solving equations by completing the square method

Find the maxima and minima - equal pi, 1) Find the maxima and minima of f(x...

1) Find the maxima and minima of f(x,y,z) = 2x + y -3z subject to the constraint 2x^2+y^2+2z^2=1 2) Compute the work done by the force ?eld F(x,y,z) = x^2I + y j +y k in moving

Express the statement as a disjunction in dnf, State the following statemen...

State the following statement as a disjunction (in DNF) as well using quantifiers: There does not exit a woman who has taken a flight on each airline in the world.

Why is the steepness of a curve partially calculate, Can you explain why is...

Can you explain why is the steepness of a curve partially calculated by the units of measurement?

Abstract algebra, group

group

Assignment 18 - area, answer sheet

answer sheet

What is set, What is a set? Explain various methods to represent a set in s...

What is a set? Explain various methods to represent a set in set theory. Define the following with the help of suitable examples. (i) Singleton Set

Partial Differential Equation, Consider the wave equation u_tt - u_xx = 0 w...

Consider the wave equation u_tt - u_xx = 0 with u(x, 0) = f(x) = 1 if -1 Please provide me a detailed answer. I had worked the most part of this question and the only I would like

Proof for properties of dot product, Proof for Properties of Dot Product ...

Proof for Properties of Dot Product Proof of u → • (v → + w → ) = u → • v → + u → • w → We'll begin with the three vectors, u → = (u 1 , u 2 , ...

Give the introduction to scientific notation, Give the Introduction to Scie...

Give the Introduction to Scientific Notation? In mathematics, it can be very difficult and time-consuming to do calculations involving very large and very small numbers. This i

Y=Theea[sin(inTheeta)+cos(inTheeta)], Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷d...

Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution) Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SI

Jack 2/12/2013 2:31:28 AM example, Solve by completing the square. i. 3x² = 9x ii. 2x² + 3x + 1 = 0 Solutions i. 3x² = 9x or (3x² - 9x = 0) x² - 3x = 0 (Step 1) x² - 3x + (-(3/2)²) = -(3/2)² (Step 2) x(-(3/2)²)= 9/4 (Step 3) x -3 = + √(9/4) (step 4) (∴ x = (3/2) + (3/2)) = (3+3)/2 or (3/2) - (3/2) = (= 3 or 0) ii) 2x² + 3x + 1 = 0 or (2x² + 3x = -1) X² + (3x/2) = -(1/2) (step 1) X² + (3x/2) + (3/4)²= (3/4)² - 1/2 (step 2) (x +(3/4)²) = 1/16 (step 3) X + (3/4) = + √(1/16) X = - (3/4) = + (1/4) -(3/4) + (1/4) or -(3/4)-(1/4) X = -(1/2) or x = -1

Jack

2/12/2013 2:31:28 AM

example,

Solve by completing the square.

i. 3x² = 9x

ii. 2x² + 3x + 1 = 0

Solutions

i. 3x² = 9x or

(3x² - 9x = 0)

x² - 3x = 0 (Step 1)

x² - 3x + (-(3/2)²) = -(3/2)² (Step 2)

x(-(3/2)²)= 9/4 (Step 3)

x -3 = + √(9/4) (step 4)

(∴ x = (3/2) + (3/2))

= (3+3)/2 or (3/2) - (3/2) =

(= 3 or 0)

ii) 2x² + 3x + 1 = 0 or (2x² + 3x = -1)

X² + (3x/2) = -(1/2) (step 1)

X² + (3x/2) + (3/4)²= (3/4)² - 1/2 (step 2)

(x +(3/4)²) = 1/16 (step 3)

X + (3/4) = + √(1/16)

X = - (3/4) = + (1/4)

-(3/4) + (1/4) or -(3/4)-(1/4)

X = -(1/2) or x = -1

Write Your Message!

Name

Email id

Message

Verfication Code

User Account

All Pages