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In polynomials you have seen expressions of the form x2 + 3x - 4. Also we know that when an expression is equated to zero or some other expression, we call it an equation. The equations of the second degree in a single variable "x" or "y" are generally referred to as quadratic equations and the most general form of it is
ax2 + bx + c = 0. The roots or solution for the quadratic equation can be obtained by substituting different values for x and selecting that value for which the value of the equation is zero. The methods which we have seen in factorization of polynomials are also applicable to obtain the roots of a quadratic equation. However, in this part we look at a specific method which is only applicable to solve quadratic equations.
According to this method the roots of a quadratic equation ax2 + bx + c = 0 are
x
This is derived as follows. We have
ax2 + bx + c = 0
ax2 + bx = - c ........(1)
In order to make the LHS a perfect square, we add to to the LHS and since the equality is to be preserved we do so for the other side also. Hence we obtain
x2 +
A lotus is 2m above the water in a pond. Due to wind the lotus slides on the side and only the stem completely submerges in the water at a distance of 10m from the original positio
The production costs per week for generating x widgets is given by, C ( x ) = 500 + 350 x - 0.09 x 2 , 0 ≤ x ≤ 1000 Answer following questions. (a) What is the c
matrix of [1 4 ] [a b]=4/9
how to solve imaginary number such as like (-3v-5)² ?? Can I cancel the radical sign and the power of two ? and square the -3 and times to -5 ? hope you will answer this :) thanks
write a fortan programme to generate prime number between 1 to 100
Sketch the graphs of the following functions: (A) y = 1/(x 2 +1) (b) x= sin x,
This question is in the form of an exercise and questions designed to give you more insight into signal processing. On the Moodle site for the module there is an EXCEL file called
Provide the vector for each of the following. (a) The vector from (2, -7, 0) - (1, - 3, - 5 ) (b) The vector from (1,-3,-5) - (2, - 7, 0) (c) The position vector for ( -
compare: 643,251: 633,512: 633,893. The answer is 633,512.
what is the answers of exercise 3.1
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