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Solve the recurrence relation
T (K) = 2T (K-1), T (0) = 1
Ans: The following equation can be written in the subsequent form:
tn - 2tn-1 = 0
Here now successively replacing n by (n - 1) and then by (n - 2) and so on we obtain a set of equations.
The method is continued till terminating condition. Add these equations in such type of a way that all intermediate terms get cancelled. The equation can be rearranged as
Multiplying all the equations correspondingly by 20, 21, ..., 2n - 1 and then adding them together, we get
tn - 2nt0 = 0
or, tn = 2n
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Divide 6.8 × 10 5 by 2.0 × 10 2 . Write your answer in scientific notation? To divide numbers written in scienti?c notation and divide the ?rst numbers (6.8 ÷ 2.0 = 3.4); the
a) A palindrome is a word that reads the similar whether read from right to left or from the left to right, the word ROTOR, for example. Let be the number of words of length n,
Fermat Catalan Conjecture
Differentiate y = x x Solution : We've illustrated two functions similar to this at this point. d ( x n ) /dx = nx n -1 d (a x ) /dx= a
Multiply following. (a) (4x 2 -x)(6-3x) (b) (2x+6) 2 Solution (a) (4x 2 - x )(6 - 3x ) Again we will only FOIL this one out. (4x 2 - x )(6 - 3x) = 24x 2 -
examples of conditional probability
how do I solve 14/27 - 23/27 =
Consider the following interpolation problem: Find a quadratic polynomial p(x) such that p(x0) = y0 p’(x1) = y’1 , p(x2) = y2 where x0 is different from x2 and y0, y’1 , y2 a
Negative four is multiplied through the quantity x + 8. If 6x is then added to this, the output is 2x + 32. What is the value of x? twice the quantity x + 6 is divided by negative
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