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Example: Solve following equations.
2 log9 (√x) - log9 (6x -1) = 0
Solution
Along with this equation there are two logarithms only in the equation thus it's easy to get on one either side of the equal sign. We will also have to deal with the coefficient in front of the first term.
log9 (√x)2 = log9 (6x -1)
log9 x = log9 (6x -1)
Now that we've got two logarithms along with the similar base & coefficients of 1 on either side of the equal sign we can drop the logs & solve.
x = 6 x -1
1 = 5x ⇒ x = 1/5
Now, we do have to worry if this solution will generate any negative numbers or zeroes in the logarithms hence the next step is to plug this into the original equation & see if it does.
2 log9 (√(1/5) - log9( 6 ( 1 /5) -1) = 2 log9 (√1/5 ) - log9 ( √(1 /5)) = 0
Note that we don't have to go all the way out with the check here. We just have to ensure that once we plug in the x we don't contain any negative numbers or zeroes in the logarithms. Since we don't in this case we have the solution, it is x=(1/5)
5x + 2y = 6 -2x + y = -6
8/10 3/8
c/6 - 1/2 = 3
i want the limits of this equation
1/3h-4(2/3h-3)=2/3h-6
I need help with my Discussion 1 for week 5 please. w^2 + 30w + 81 and ac + xc + aw^2 + xw^2 and last one is x^4 - x^3
3.4% as a decimal
The measure of the smallest angle is one-third the largest angle. The measure of the middle angle is 65 less than the measure of the largest angle. Find the measures of the angles
-2x +7 =11
A police academy is training 14 new recruits. Some are working dogs and others are police officers. There are 38 legs in all. How many of each type of recruits are there?
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