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Example: Solve following equations.
2 log9 (√x) - log9 (6x -1) = 0
Solution
Along with this equation there are two logarithms only in the equation thus it's easy to get on one either side of the equal sign. We will also have to deal with the coefficient in front of the first term.
log9 (√x)2 = log9 (6x -1)
log9 x = log9 (6x -1)
Now that we've got two logarithms along with the similar base & coefficients of 1 on either side of the equal sign we can drop the logs & solve.
x = 6 x -1
1 = 5x ⇒ x = 1/5
Now, we do have to worry if this solution will generate any negative numbers or zeroes in the logarithms hence the next step is to plug this into the original equation & see if it does.
2 log9 (√(1/5) - log9( 6 ( 1 /5) -1) = 2 log9 (√1/5 ) - log9 ( √(1 /5)) = 0
Note that we don't have to go all the way out with the check here. We just have to ensure that once we plug in the x we don't contain any negative numbers or zeroes in the logarithms. Since we don't in this case we have the solution, it is x=(1/5)
Harold’s movie theater increased the price of admission 20%. Tickets had sold for $7.00. What is the current ticket price? Percent of Decrease: 3. Original Price: $45
If you sell a kayak for $400 and your sales per day averages $5200. Assume the sales per day is a linear function of price of kayak. write an equation describing the relationship.
y+7 3y-2 --- = 1 + ---- 3 5
what is the slope of x+y=5 and x-y=3
how would i solve one of these functions. like how would i find the domain and range? and may i get an example.
how do you find the solution using linear combinations 4x+3y=-1 and -3x+-5y=9
Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is. 1. Determine the vertex. We'll discus
x+6=2x+5
Linda has a total of 225 on 3 tests. The sum of the scores on the first and second tests exceeds her third score by 61. Her first test exceeds her second by 6 points. Find Linda''s
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