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Example: Solve following.
| 10 x - 3 |= 0
Solution
Let's approach this one through a geometric standpoint. It is saying that the quantity in the absolute value bars has a distance of zero from the origin. There is just one number that has the property and i.e. zero itself. Thus, we must have,
10x - 3 = 0 ⇒ x = 3/10
In this case we acquire a single solution.
Thus, if b is zero then we can just drop the absolute value bars and solve the equation. Likewise, if b is negative then there will be no solution to the equation.
To this point we've only looked at equations which involve an absolute value being equivalent to a number, however there is no cause to think that there ought to only be a number on the other side of the equal sign. Similarly, there is no cause to think that we can only have one absolute value in the problem. Thus, we have to take a look at a couple of these kinds of equations.
Multiply 2(b + 5)
(2x^2+16x+24)/(3x^2) /(x+6)
what the hell is the problem to this solution .
30. 5x-1 greater than 29
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you can use the equation -b +or- Square root of bsquared - 4(a)(c)over 2a. But if you number for b is b is negative it will become positive??? And if the number was + it will Beco
Now, let's solve out some double inequalities. The procedure here is alike in some ways to solving single inequalities and still very different in other ways. As there are two ineq
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