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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
When finding the limit as x approaches 0 the for function (square root of x^3 + x^2) cos(pi/2x) would the limit not exist because there would be a zero in the denominator?
LCD
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