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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
The remainder when 5^99 is divided by 13 Ans) 8 is the remainder.
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