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Solve sin (3t ) = 2 .
Solution
This example is designed to remind you of certain properties about sine and cosine. Recall that -1 ≤ sin (θ ) ≤ 1 and -1 ≤ cos(θ ) ≤ 1 . Thus, as sine will never be greater that 1 it definitely can't be two. Hence THERE ARE NO SOLUTIONS to this equation!
It is significant to remember that not all trig equations will have solutions.
Theorem, from Definition of Derivative If f(x) is differentiable at x = a then f(x) is continuous at x =a. Proof : Since f(x) is differentiable at x = a we know, f'(a
#question.2157\7625.
how to get harmonic problems with answer
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