Solve for, if tan5 = 1, Mathematics

Assignment Help:

a)Solve for ?, if tan5? = 1.

Ans:    Tan 5? = 1        ⇒ ? =45/5 ⇒ ?=9o.

b)Solve for ? if Sin?/1 + Cos? + 1 + Cos?/ Sin? = 4 .

Ans:  Sin?/1 + Cos? + 1 + Cos?/ Sin? = 4

Sin2?/1 + 1 (Cos?)2/ Sin?(1 + Cos?) = 4

 

Sin2?+1 + Cos2? + 2cos?/ Sin? +Sin?Cos? = 4

2 +2Cos? / Sin?(1+ cos?) =4

2+(1+ cos?)/Sin?(1+ cos?) = 4

 

 

 

 

2/sin? = 4

sin ? = 1/2

sin ? = sin 30

? = 30o

 


Related Discussions:- Solve for, if tan5 = 1

Subtangents & subnormals, show that the subtangent at any point on parabola...

show that the subtangent at any point on parabola y2 =4ax is twice the abscissa at that point.

What is angle pairs in parallel lines, What is Angle Pairs in Parallel Line...

What is Angle Pairs in Parallel Lines ? Next, we introduce several angle pairs formed by transversals which are very important in our study of geometry. Alternate interior an

Geometry, RS=8y+4 ST=4y+8 RT=15y-9 a.) WHAT IS THE VALUE OF y b.) FIND RS...

RS=8y+4 ST=4y+8 RT=15y-9 a.) WHAT IS THE VALUE OF y b.) FIND RS, ST, AND RT

Solve by factorization, Solve by factorization X 2 +(a/a+b + a+b/a)x+...

Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 =>  X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) =>  X[x+a/a+b] +a+b/a[a+a*a+b]= 0 =>  X= -a

Geometry, triangular with base AB = 48cm and height CH=16cm is inscribed a ...

triangular with base AB = 48cm and height CH=16cm is inscribed a rectangle MNPQ in which MN: MQ = 9:5 Find MN and MQ

Expertes, how to do multiplication

how to do multiplication

Word problems, A baseball card was worth $5.00 in 1940. It doubled in value...

A baseball card was worth $5.00 in 1940. It doubled in value every decade. How much was it worth in 2000?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd