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Solve by simplex method
Subject to
3x1 + 5x2 ≤ 15
5x1 + 2x2 ≤ 10
& x1 ≥ 0, x2 ≥ 0
[Ans. Max Z = 235/19, x1= 20/19, x2= 45/19]
x1 + x2 ≤ 4
3x1 - 8x2 ≤ 24
10x1 + 7x2 ≤ 35
[Ans. Max Z = 28, x1= 0, x2= 4]
x1 + 3x2 + x4 ≤ 4
2x1 + x2 ≤ 3
x2 + 4x3 + x4 ≤ 3
& x1 ≥ 0, x2 ≥ 0, x3 ≥ 0, x4 ≥ 0
[Ans. Max Z = 13/2, x1= 1, x2= 1, x3= 1/2, x4= 0]
-x1 - 2x2 ≥ -6
4x1 + 3x2 ≤ 12
[Ans. Max Z = 21, x1= 3, x2= 0]
2x1 + x2 ≤ 10
x1 + 3x2 ≤ 6
x1 + x2 ≤ 21
Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 = 4 X1 - X2 = 2 X1, X2 = 0
Consider the closed network of the following figure. The number at the arrows give the transition probabilities for a customer leaving the queue to route to a subsequent queue. Eve
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advantages of northwest corner method
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