Solve by simplex method, Operation Research

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Solve by simplex method

  1. Maximize Z = 5x1 + 3x2

Subject to

3x1 + 5x2 ≤ 15

5x1 + 2x2 ≤ 10

&         x1 ≥ 0, x2  ≥ 0

[Ans. Max Z = 235/19, x1= 20/19, x2= 45/19]

 

  1. Maximize Z = 5x1 + 7x2

Subject to

x1 + x2 ≤ 4

3x1 - 8x2 ≤ 24

10x1 + 7x2 ≤ 35

&         x1 ≥ 0, x2  ≥ 0

[Ans. Max Z = 28, x1= 0, x2= 4]

 

 

 

 

  1. Maximize Z = 2x1 + 4x2 + x3+ x4

Subject to

x1 + 3x2 + x4 ≤ 4

2x1 + x2 ≤ 3

x2 + 4x3 + x4 ≤ 3

&         x1 ≥ 0, x2  ≥ 0, x3  ≥ 0, x4  ≥ 0

[Ans. Max Z = 13/2, x1= 1, x2= 1, x3= 1/2, x4= 0]

 

  1. Maximize Z = 7x1 + 5x2

Subject to

-x1 - 2x2 ≥ -6

4x1 + 3x2 ≤ 12

&         x1 ≥ 0, x2  ≥ 0

[Ans. Max Z = 21, x1= 3, x2= 0]

 

  1. Maximize Z = 3x1 + 2x2

Subject to

2x1 + x2 ≤ 10

x1 + 3x2 ≤ 6

x1 + x2 ≤ 21

&         x1 ≥ 0, x2  ≥ 0


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