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Solve by simplex method
Subject to
3x1 + 5x2 ≤ 15
5x1 + 2x2 ≤ 10
& x1 ≥ 0, x2 ≥ 0
[Ans. Max Z = 235/19, x1= 20/19, x2= 45/19]
x1 + x2 ≤ 4
3x1 - 8x2 ≤ 24
10x1 + 7x2 ≤ 35
[Ans. Max Z = 28, x1= 0, x2= 4]
x1 + 3x2 + x4 ≤ 4
2x1 + x2 ≤ 3
x2 + 4x3 + x4 ≤ 3
& x1 ≥ 0, x2 ≥ 0, x3 ≥ 0, x4 ≥ 0
[Ans. Max Z = 13/2, x1= 1, x2= 1, x3= 1/2, x4= 0]
-x1 - 2x2 ≥ -6
4x1 + 3x2 ≤ 12
[Ans. Max Z = 21, x1= 3, x2= 0]
2x1 + x2 ≤ 10
x1 + 3x2 ≤ 6
x1 + x2 ≤ 21
difference between simplex solution procedure for maximisation and minimisation
#queSix Operators are to be assigned to five jobs with the cost of assignment in Rs. given in the matrix below. Determine the optimal assignment. Which operator will have no assign
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Maximize6x1+8x2+5x3,st,labour3x1+4x2+5x3 =0 then brefly explain x1,x2,x3;term labour,metal&plastic;the160hours;x1,x2&x3>=0
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Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 4 X1+ X2 2 X1, X2 0on..
This year Jan Rich, who is ranked number one in women''s singles in tennis, and Marie Wacker, who is ranked number three, will play 4 times. If Marie can beat Jan 3 times, she will
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