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Solve the subsequent IVP.
dv/dt = 9.8 - 0.196v; v(0) = 48
Solution
To determine the solution to an Initial Value Problem we should first determine the general solution to the differential equation and after that use the initial condition to recognize the precise solution which we are after. Thus, since this is the similar differential equation as we looked at in Illustration 1, we previously have its general solution.
v(t) = 50 + ce-0.196t
Currently, to determine the solution we are after we require identifying the value of c which will give us the solution we are after. To do such we simply plug in the first condition that will provide us an equation we can resolve for c. Thus let's do this as:
48 = v () = 50 + c ⇒ c = -2
Therefore, the actual solution to the Initial Value Problem is.
v(t) = 50 - 2 e-0.196t
A graph of this solution can be observed in the figure above.
Let's do a couple of illustrations which are a little more included.
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modular arithematic
40.783-75
how can i evaluate this lim of x as x approaches to a
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