Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Solve the subsequent IVP.
dv/dt = 9.8 - 0.196v; v(0) = 48
Solution
To determine the solution to an Initial Value Problem we should first determine the general solution to the differential equation and after that use the initial condition to recognize the precise solution which we are after. Thus, since this is the similar differential equation as we looked at in Illustration 1, we previously have its general solution.
v(t) = 50 + ce-0.196t
Currently, to determine the solution we are after we require identifying the value of c which will give us the solution we are after. To do such we simply plug in the first condition that will provide us an equation we can resolve for c. Thus let's do this as:
48 = v () = 50 + c ⇒ c = -2
Therefore, the actual solution to the Initial Value Problem is.
v(t) = 50 - 2 e-0.196t
A graph of this solution can be observed in the figure above.
Let's do a couple of illustrations which are a little more included.
how to solve
QUESTION (a) Draw a graph model with the following adjacency matrix. (b) The diagram below shows different cities labelled a to g and z. Also sh
carlie is now fivetimes as old as henry. in nine years her age will be twice henry''s age then. how old is carly now
How tall does a cone with diameter of 10 inches have to be to fit exactly half of a sphere with a diameter of 10 inches inside it?
Find the normalized differential equation which has {x, xex} as its fundamental set
Definition of limit : Consider that the limit of f(x) is L as x approaches a & write this as provided we can make f(x) as close to L as we desire for all x adequately clos
Marci filled her car's gas tank on Monday, and the odometer read 32,461.3 miles. On Friday while the car's odometer read 32,659.7 miles and she filled the car's tank again. It will
ABC is a right-angled isosceles triangle, right-angled at B. AP, the bisector of ∠BAC, intersects BC at P. Prove that AC 2 = AP 2 + 2(1+√2)BP 2 Ans: AC = √2AB (Sinc
the value of square root of 200multiplied by square root of 5+
How can I submit a sample of my work in either teaching online or checking homework as I am retired and doing this for the first time?
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd