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For a first order linear differential equation the solution process is as given below:
1. Place the differential equation in the correct initial form, (1).
2. Determine the integrating factor, µ (t) and using (10).
3. Multiply everything in the differential equation through µ (t) and verify that the left side turns into the product rule (µ (t) y(t))' and write this as such.
4. Integrate both sides; ensure you properly deal along with the constant of integration.
5. Resolve for the solution y(t).
If a+b+c = 3a , then cotB/2 cotC/2 is equal to
1 1/3:2/3:1/6
how to multply
There actually isn't a whole lot to do throughout this case. We'll find two solutions which will form a basic set of solutions and therefore our general solution will be as,
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there are 300 students in the sixth grade. if 40% of them were girls, how many boys were there?
A solution to a differential equation at an interval α Illustration 1: Show that y(x) = x -3/2 is a solution to 4x 2 y′′ + 12xy′ + 3 y = 0 for x > 0. Solution : We'll
What is polygon? A polygon is a shape with three or more sides, in which each side touches another only at its endpoints. Some polygons that you are probably already familiar w
Next we have to talk about evaluating functions. Evaluating a function is in fact nothing more than asking what its value is for particular values of x. Another way of looking at
det(adj A)for 1*1 matrix
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