Solution of linear equation, Mathematics

Assignment Help:

Solution of Linear Equation

How to solve a linear equation? Please assist me.

Related Discussions:- Solution of linear equation

Fractions, how do you convert in a quicker way?

how do you convert in a quicker way?

what are the coordinates of the vertex , Use the graph of y = x2 - 6x to ...

Use the graph of y = x2 - 6x to answer the following: a) Without solving the equation (or factoring), determine the solutions to the equation x 2 - 6x = 0 usi

Doubles Plus 1 and Doubles Minus 1, Write the doubles fact you used to solv...

Write the doubles fact you used to solve the problem. 7 + 8 = 15

Division, 32/562

32/562

Simplify the boolean function, Simplify the Boolean function: F...

Simplify the Boolean function: F (w,x,y,z) = ∑ (0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) (8) Ans: f(w, x, y, z) = ∑(0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) The above

Determine the order of the local truncation error, The backwards Euler diff...

The backwards Euler difference operator is given by for differential equation y′ = f(t, y). Determine the order of the local truncation error. Explain why this difference o

Problems with applying algorithms , PROBLEMS WITH APPLYING ALGORITHMS : F...

PROBLEMS WITH APPLYING ALGORITHMS : From your experience, you would agree that children are expected to mechanically apply the algorithms for adding or subtracting numbers, regar

Learning and formulating maths teaching strategies, Before going further, l...

Before going further, let us repeat an aspect of learning which is useful to keep in mind while formulating teaching strategies. A child who can add or subtract in the context of s

Quadratic equation, If roots of (x-p)(x-q) = c are a and b what will be th...

If roots of (x-p)(x-q) = c are a and b what will be the roots of (x-a)(x-b) = -c please explain. Solution) (x-p)(x-q)=c x2-(p+q)x-c=0 hence, a+b=p+q and a.b=pq-c

Solve factors for given equations, 1/a+b+x =1/a+1/b+1/x a+b ≠ 0 ...

1/a+b+x =1/a+1/b+1/x a+b ≠ 0 Ans: 1/a+b+x =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒ x - ( a + b + x )/ x ( a + b + x ) = + a + b/ ab ⇒

james 2/12/2013 2:02:22 AM the solution procedure of linear equation is: Suppose that M, N, and P are expressions that may or may not include variables, and then the following constitute some rules that will be helpful in the solution of linear equations Rule 1: Additional rule If M = N then M + P = N + P Rule 2: Subtraction rule If M = N, Then M - P = N - P Rule 3: multiplication rule If M = N and P ≠ O then M x P = N x P Rule 4: Division rule If P x M = N and P ≠ O And N/P = Q Q being a material number then M = N/P

james

2/12/2013 2:02:22 AM

the solution procedure of linear equation is:

Suppose that M, N, and P are expressions that may or may not include variables, and then the following constitute some rules that will be helpful in the solution of linear equations

Rule 1: Additional rule

If M = N then M + P = N + P

Rule 2: Subtraction rule

If M = N, Then M - P = N - P

Rule 3: multiplication rule

If M = N and P ≠ O then M x P = N x P

Rule 4: Division rule

If P x M = N and P ≠ O

And N/P = Q Q being a material number then

M = N/P

Write Your Message!

Name

Email id

Message

Verfication Code

User Account

All Pages