Solution of basic linear equation, Algebra

Assignment Help:

Solve following equations.

(a)   x2 -100 = 0

 (b) 25 y 2 - 3 = 0

Solution

There actually isn't all that much to these problems.  To use the square root property all that we have to do is get the squared quantity on the left side by itself along with a coefficient of 1 and the number on the other side. Once it is done we can employ the square root property.

 (a)

             x2 -100 + 0

It is a fairly simple problem thus here is the work for this equation.

x2  = 100

 x = ± 100 = ±10

Thus, there are two solutions to this equation,

x =±10 .  Remember it means that there are really two solutions here, x = -10 and x =10 .

 (b) 25 y 2 - 3 = 0

The main difference among this one & the previous one is the 25 in front of the squared term.  The square root property desired a coefficient of one there. That's simple enough to deal with but; we'll just divide both sides through 25.  Here is the work for this equation.

                                          25 y 2  = 3

y 2  = 3/25

⇒         y = ±√(3/5) = ±(√3 )/5

In this the solutions are a little messy, but several of these will do so don't worry regarding that. Also note that since we knew what the square root of 25 was we went ahead & split the square root of the fraction up as illustrated.  Again, recall that there are actually two solutions here, one positive & one negative.


Related Discussions:- Solution of basic linear equation

Evaluate log function, Example    Evaluate log 5 7 . Solution At f...

Example    Evaluate log 5 7 . Solution At first, notice that we can't employ the similar method to do this evaluation which we did in the first set of instance. It would n

Fraction, a carpenter had a 20 ft piece of lumber which he cut into 3 piece...

a carpenter had a 20 ft piece of lumber which he cut into 3 pieces. one piece was 7 1/3 ft long and other was 6 1/2 ft long. how long was the remaining piece?

Word problems, A mountain has an elevation of 19,389 feet in 1918, the glac...

A mountain has an elevation of 19,389 feet in 1918, the glacier on this peak covered 4 acres. By 2003 this glacier had melted to 1 acre. What was the yearlyrate of change and what

Rates, find the number of hours it would take to drive 168 miles at an aver...

find the number of hours it would take to drive 168 miles at an average rate of 48 miles an hour. use the formula d=rt

Complex solutions of quadratic equations, These are the only possibilities ...

These are the only possibilities for solving quadratic equations in standard form.  However Note that if we begin with rational expression in the equation we might get different so

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd