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Slab hanging:
Three similar uniform slabs each having length '2a' are resting on edge of table as shown in the figure given below. If each slab is overhung by the maximum possible amount, find out amount by which bottom slab is overhanging. As the bottom beam overhang by a/3 amount
Sol.: The maximum overhang of the top beam is 'a',
Now taking moment about the point A2, considering all the load acting on middle beam.
-W(a - X) + W.X = 0
on solving X = a/2 ...(i)
Now taking the moment about point A3
-W(a - Y) + W[Y - (a - X)] + W(X + Y) = 0
-Wa + WY + WY - Wa + WX + WX + WY = 0
3Y - 2a + 2X = 0
Y = a/3 .......ANS
slip of belt
1. I have a data for displacement versus time ( graph) then I want to get the velocity and acceleration graphs from the displacement.How can I get it?
Q. W rite down the basic formula for maximum bending moment in some ideal cases. Sol.: Ber m together with nature of load Maximu
Find out force on each member - Truss: A truss is as shown in the figure given below. Find out force on each member and the nature of it. Sol.: First we calculate sup
What is ignition angle offset
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