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The size of stack was declared as ten. Thus, stack cannot hold more than ten elements. The major operations which can be performed onto a stack are push and pop. However, in a program, we have to provide two more options, namely, show elements & exit. Show elements will display the elements of the stack. In particular case, the user is not interested to carry out any operation onto the stack and would like to get out of the program, and then s/he will choose exit option. It will log the user out of the program. Choice is a variable that will enable the user to choose the option from the push, pop, show elements & exit operations. top points towards the index of the free location in the stack to where the next element can be pushed. Element is the variable that accepts the integer that need to be pushed onto the stack or will hold the top element of the stack which has to be popped from the stack. The array stack can hold at most ten elements. Push & pop will carry out the operations of pushing the element to the stack & popping the element from the stack respectively.
Explain the representations of graph. The different ways of representing a graph is: Adjacency list representation : This representation of graph having of an array Adj of
loops
Generally, Computational complexity of algorithms are referred to through space complexity (space needed for running program) and time complexity (time needed for running the progr
I need a person who has a good background in using R. Studio? In adition, a person who is good in using algorithms.
what is tree
Linked list representations contain great advantages of flexibility on the contiguous representation of data structures. However, they contain few disadvantages also. Data structur
Ask question #Minima binary search tree is used to locate the number 43 which of the following probe sequences are possible and which are not? explainum 100 words accepted#
What will be depth do , of complete binary tree of n nodes, where nodes are labelled from 1 to n with root as node and last leaf node as node n
1. Use the Weierstrass condition, find the (Strongly) minimizing curve and the value of J min for the cases where x(1) = 0, x(2) = 3. 2. The system = x 1 + 2u; where
In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore
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