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The size of stack was declared as ten. Thus, stack cannot hold more than ten elements. The major operations which can be performed onto a stack are push and pop. However, in a program, we have to provide two more options, namely, show elements & exit. Show elements will display the elements of the stack. In particular case, the user is not interested to carry out any operation onto the stack and would like to get out of the program, and then s/he will choose exit option. It will log the user out of the program. Choice is a variable that will enable the user to choose the option from the push, pop, show elements & exit operations. top points towards the index of the free location in the stack to where the next element can be pushed. Element is the variable that accepts the integer that need to be pushed onto the stack or will hold the top element of the stack which has to be popped from the stack. The array stack can hold at most ten elements. Push & pop will carry out the operations of pushing the element to the stack & popping the element from the stack respectively.
Tree is dynamic data structures. Trees can expand & contract as the program executes and are implemented via pointers. A tree deallocates memory whereas an element is deleted.
Link list representation of a circular queue is more efficient as it employs space more competently, of course with the added cost of storing the pointers. Program 7 gives the link
Illustrates the program segment for Quick sort. It uses recursion. Program 1: Quick Sort Quicksort(A,m,n) int A[ ],m,n { int i, j, k; if m { i=m; j=n+1; k
Define Minimum Spanning Tree A minimum spanning tree of a weighted linked graph is its spanning tree of the smallest weight, where the weight of a tree is explained as the sum
Illustrate Trivariate Colour Models Conventional colour models based on the tristimulus theory all contain three variables and so are called trivariate models. Let us now consi
loops
Relation between the time and space complexities of an algorithm The examining of algorithm focuses on time complexity and space complexity. As compared to time analysis, the a
Step-1: For the current node, verify whether it contain a left child. If it has, then go to step-2 or else go to step-3 Step-2: Repeat step-1 for left child Step-3: Visit (th
Write a program to create a hashed file that stores the records currently in the file " data_2013 ". Records should use the same fixed-length schema given previously, and should ag
Write the algorithm for compound interest
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