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At time t when an infected machine scans and finds a vulnerable machine, the vulnerable one will be compromised and start to scan and infect others at time t+X, where X is a r.v. following Geometric distr. with p=0.1 (i.e., P(X=k) = (1-p)k-1p, k=1,2,3,... ). All other parameters are the same as in the first simulation task. Draw a figure shows the averaged I(t) (average over 100 simulation runs) for this worm propagation compared with the averaged simulated I(t) from the first simulation task.
Utility Functions - artificial intelligence: A goal based on an agent for playing chess is infeasible: at every moment it decides which move to play next, it sees whether that
why we don''t use register at the place of ram?
How can we change almost any algorithm to have a good best case running time? Check whether the input constitutes an input at the very starting Or else run the original algo
Access to External Identifiers: An external identifier is one which is referred in one module though defined in another. You can declare an identifier to be external by including i
Realized mean that the component has been painted on screen or that is prepared to be painted. Realization can take place by invoking any of these methods. setVisible(true), show()
Reduce the following equation using k-map Y = BC‾D‾ + A‾BC‾D + ABC‾D + A‾BCD + ABCD Ans. Multiplying the first term with (A+A') Y = A'BC'D' + ABC'D' + A'BC'D + ABC'D + A'BCD +
Q. How do you classify the neutrons in terms of its kinetic energy? Neutrons are classified as-per to their kinetic energy as (a) Slow neutrons as well as (b) fast neutrons.
Define the Don't Care States - Simplifying K Maps? The Truth table specifications for a logic function may not to include all possible combinations of the input binary digits for
A combinational circuit has 3 inputs A, B, C and output F. F is true for following input combinations A is False, B is True A is False, C is True A, B, C are
I think yes...so if 8259 gives interrupt then it will be serviced instantly but since into pin is left hanging the insr bit will never be set...and so whenever any interrupt occurs
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