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Simplify the given expressions using Boolean postulates
XY + X‾Z‾ + XY‾Z (XY + Z)
Ans. XY + X‾Z‾ + XY‾Z (XY + Z)= XY + X‾Z‾ + XY‾Z (XY + Z)= XY + X‾Z‾ + XXYY‾Z + XY‾ZZ= XY + X‾Z‾ + XYZ (As YY‾ = 0 and ZZ = Z)= XY + X‾ + Z‾ + XY‾Z (As X‾Z‾ = X‾ + Z‾)= X‾ + XY + Z‾ + XY‾Z= X‾ + X (Y + Y‾Z) + Z‾= X‾ + X (Y +Z) + Z‾ (As Y + Y‾Z = Y+Z)= X‾ + X Y (Z+ Z‾ ) + XZ + Z‾ (As Z+ Z‾ =1)= X‾ + X Y Z + XYZ‾ + XZ + Z‾= X‾ + XZ (1+ Y) + Z‾ (1+XY)= X‾ + XZ + Z‾ (As 1+ Y = 1 and 1+XY = 1)= X‾ + XZ) + Z‾=(X‾ + Z) + Z‾ (As X‾ + XZ = X‾ + Z‾= X‾ +( Z + Z‾)= X‾ +1 (As Z + Z‾ = 1)=1 (As X‾ +1 = 1)
How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB ? Ans. Here three product terms, therefore three AND gates of two inputs are needed.
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