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The Boolean expression A‾.B + A.B‾ + A.B is equivalent to ?
Ans. The Boolean expression A‾ .B + A. B‾+ A.B is equivalent to A + B
(A‾ .B + A. B‾+ A.B = B( A‾ + A) + A. B‾= B + A. B‾ {Q ( A‾ + A) = 1}= A + B {Q (B + A.B‾) = B + A}
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We will be using data from the 2008 Canadian General Election Study.1 The data can be found on the course page. As well, there are three other documents (loosely called "codebooks"
Q. Prove using Boolean Algebra 1. AB + AC + BC' = AC + BC' 2. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A 3. (A+B) (A'+B'+C) + AB = A+B 4. A'C + A'B + AB'C + BC = C + A'B
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State the term- $display and $write $display and $write two are the same except which $display always prints a newline character at the end of its execution.
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