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Simplest equivalent circuit topology using lumped elements:
For each of the Smith chart traces below, sketch (at the right of each chart) the simplest equivalent circuit topology using lumped elements. Note that the first chart's trace does not lie exactly on the unit circle:
The chart traces on the right side both begin at f=1.0 GHz and lie approximately on the r=0.5 circle, starting at the x=-2.0 circle. With this information, find the values (to two significant digits) of the two components that at 1 GHz dominate the equivalent circuits you've drawn.
An audio amplifier with feedback needs gain of approximately 500 in a 3-dB bandwidth extending from 60 Hz to 25 kHz. Assume this is accomplished using a feedback network with ß=0.0
Calculate the cross-sectional area, in mm 2 , of a piece of aluminium wire 100 m long and having a resistance of 2Ω. Take the resistivity of aluminium as 0.03 x 10-6 Ωm.
What is Voltage Multiplying DACs? Multiplying DACs function on the principle of producing a weighted sum analog signal where the sum is proportional to the digital input signal
What is segmentation? Segment memory addressing divides the memory in several segments. All of these segments can be seen as a linear memory space. All of these segments are ad
Q. Reduce the circuit of Figure to a Thévenin and a Norton equivalent circuit with respect to terminals a-b.
A three-phase transposed line is composed of one ACSR conductor per phase with flat horizontal spacing of 11 meters as shown in Figure (a). The conductors have a diameter of 3.625
Q. What are the advantages and disadvantages of a R-C coupled amplifier. Advantages · It has excellent frequency response. The gain is constant over the audio frequency ra
Q. For the circuit shown in Figure, find the phasor values (with peak magnitudes) of ¯I, ¯V R , ¯V L , and ¯V C by using PSpice.
A communication system for a voice-band (3 kHz) channel is designed for a received SNR E b /N 0 at the detector of 30 dB when the transmitter power is Ps =-3 dBW. Find the value o
Explain priority interrupts of 8085. The 8085 microprocessor has five interrupt inputs. They are TRAP, RST .5, RST 6.5, RST 5.5, and INTR. These interrupts have a fixed prio
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