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SIMILAR TRIANGLES : Geometry is the right foundation of all painting, I have decided to teach its rudiments and principles to all youngsters eager for art. (Ans: r=2)
Example
ABC is a right-angled triangle, right-angled at A. A circle is inscribed in it. The lengths of the two sides containing the right angle are 6cm and 8 cm. Find the radius of the in circle.
Ans: BC = 10cm
y + z = 8cm
x + z = 6cm
x + y = 10
⇒ x + y + z = 12
z = 12 - 10
z = 2 cm
∴radius = 2cm
Circles In this section we are going to take a rapid look at circles. Though, prior to we do that we have to give a quick formula that expectantly you'll recall seeing at som
1/a+b+x =1/a+1/b+1/x a+b ≠ 0 Ans: 1/a+b+x =1/a+1/b+1/x => 1/a+b+x -1/x = +1/a +1/b ⇒ x - ( a + b + x )/ x ( a + b + x ) = + a + b/ ab ⇒
A man invests rs.10400 in 6%shares at rs.104 and rs.11440 in 10.4% shares at rs.143.How much income would he get in all??
In a periscope, a pair of mirrors is mounted parallel to each other as given. The path of light becomes a transversal. If ∠2 evaluate 50°, what is the evaluation of ∠3? a. 50°
Find out some solutions to y′′ - 9 y = 0 Solution We can find some solutions here simply through inspection. We require functions whose second derivative is 9 times the
We know that one has to deal with numbers in day-to-day life irrespective of his inclination and field of work. Also one cannot refute the fact
i need help trying make a presentation for my teacher
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from 0->1: Int sqrt(1-x^2) Solution) I=∫sqrt(1-x 2 )dx = sqrt(1-x 2 )∫dx - ∫{(-2x)/2sqrt(1-x 2 )}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x 2 ) - ∫-x 2 /√(1-x 2 ) Let
3. How are Indian customers visiting Shoppers’ Stop any different from customers of developed western countries? 4. How should Shoppers’ Stop develop its demand forecasts?
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