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SIMILAR TRIANGLES : Geometry is the right foundation of all painting, I have decided to teach its rudiments and principles to all youngsters eager for art. (Ans: r=2)
Example
ABC is a right-angled triangle, right-angled at A. A circle is inscribed in it. The lengths of the two sides containing the right angle are 6cm and 8 cm. Find the radius of the in circle.
Ans: BC = 10cm
y + z = 8cm
x + z = 6cm
x + y = 10
⇒ x + y + z = 12
z = 12 - 10
z = 2 cm
∴radius = 2cm
sin (cot -1 {cos (tan -1 x)}) tan -1 x = A => tan A =x sec A = √(1+x 2 ) ==> cos A = 1/√(1+x 2 ) so A = cos -1 (1/√(1+x 2 )) sin (cot -1 {cos (tan -1 x)}) = s
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I am really stuck on this topic and other topics its extremely difficult and I dont know what to do Im stressing out help me please.
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