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SIMILAR TRIANGLES : Geometry is the right foundation of all painting, I have decided to teach its rudiments and principles to all youngsters eager for art. (Ans: r=2)
Example
ABC is a right-angled triangle, right-angled at A. A circle is inscribed in it. The lengths of the two sides containing the right angle are 6cm and 8 cm. Find the radius of the in circle.
Ans: BC = 10cm
y + z = 8cm
x + z = 6cm
x + y = 10
⇒ x + y + z = 12
z = 12 - 10
z = 2 cm
∴radius = 2cm
Differentiate y = x x Solution : We've illustrated two functions similar to this at this point. d ( x n ) /dx = nx n -1 d (a x ) /dx= a
What is modi method?
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X and Y are centers of circles of radius 9cm and 2cm and XY = 17cm. Z is the centre of a circle of radius 4 cm, which touches the above circles externally. Given that XZY=90 o , w
Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C. Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0
Uh on my homework it says 6m = $5.76 and I dont get it..
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why arcsin(sinq)=pi-q [pi/2 3pi/2]
Consider the following linear programming problem: Min (12x 1 +18x 2 ) X 1 + 2x 2 ≤ 40 X 1 ≤ 50 X 1 + X 2 = 40 X
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