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If 7sin2?+3cos2? = 4, show that tan? = 1/√3 .
Ans: If 7 Sin2? + 3 Cos2? = 4 S.T. Tan? 1/√3
7 Sin2? + 3 Cos2? = 4 (Sin2? + Cos2?)
⇒ 3 Sin2? = Cos2?
Sin 2? / Cos 2? = 1/3
⇒ Tan2? = 1/3
Tan? = 1/√3
Multiply and divide by root2, then root2/root2(sinx+cosx) = root2(sinx/root2 + cosx/root2) = root2(sinx cos45+cosx sin45) = root2(sin(x+45))
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