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Q. Show output Characteristic Of Common Emitter Configuration?
Output characteristics: This family of curves may be divided into three regions just as was done for common base configuration. They are active region, saturation region and cut off region. In the active region the collector junction is reverse biased and the emitter junction is forwad biased. The active region is the area right of the ordinate VCE=a few tenths of a volt and above IB=0.In this region the transistor output current responds most sensitively to an input signal.If the transistor is to be used as an amplifying device without appreciable distortion it must be restricted to operate in this region.
The common emitter characteristics in the active region are readily understood qualitatively on the basis of common base configuration. From Kirchoff's current law the base current is
IB = -(IC+IE)
IC = Ico+α IIB/1- α
If we define β by
β= I/1-I
IC= (1+ β) Ico + βIB
Q. For DSB and conventional AM, obtain expressions for the in-phase and quadrature components x d (t) and x q (t), and envelope and phase v(t) and φ(t).
The Series Resistance rule
Q. What are the different types of coupling in amplifiers? The coupling between stages of amplifications may also be used to classify amplifiers. There are four main groups: di
Derive Lame's equation for a thick cylinder subjected to internal pressure with clean diagrams. Evaluate the maximum and minimum hoop stresses across the section of a pipe of400
ohm''s law
Referring to Figure, let boxes 2, 3, and 5 consist of a 0.2-H inductor, a 5- resistor, and a 0.1-F capacitor, respectively. Given A = 5, and v 1 = 10 sin 10t, i 2 = 5 sin 10t ,
Connect the two signals used in section 2 above to the "Multiplier" module. Make sure that you record the amplitude of each signal. Observe and record the resultant waveform in
First Quadrant or Class A chopper A chopper two mode operation of class A chopper can be explained as follow.
what is scott connection
The LEDs should also show the rounded percentage of the full scale output. Since there are 8 LEDs every one represents 12.5%. Though, since we want the rounded percentage the LED o
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