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Q. For a transistor, when vGS = -2.0 V, find VDSsat if Vp= -4.0 V for an n-channel depletion mode MOSFET.
Solution:
Vp= -(VDSsat + vSG)but vSG = -vGS = -(-2.0) VSubstituting this in the above equation;
-4.0 V = -(VDSsat + 2.0 V)
ie VDSsat = 2.0 V
This is the value of vDS where the pinch-off will occur for the given gate-to-source voltage.
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