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Q. Show Equilibrium expression for water?
Ans.
The equilibrium expression for water is equal to a constant, Kw. This constant is called the ion product of water and is equal to 1.0 x 10-14:
Kw = [H+] [OH-] = 1.0 -> 10-14
There are two equilibrium constants, Ka and Kb, which are useful in describing the strength of acids and bases.
Suppose H-A and B-OH are an acid and base, respectively. Then Ka and Kb are defined as follows:
H-A -> H+ + A- Ka = [H+] [A-] / [H-A]
B-OH -> B+ + OH- Kb = [B+] [OH-] / [B-OH]
The higher Ka or Kb is, the greater the degree of ionization by the acid or base.
The allylic carbons are indicated with an asterisk (*).
Benzylic halide follows sn1 mechanism always...............the order of halides going sn1 rxn is BENZYL>ALLYL>TERTIARY>SECONDARY>PRIMARY>METHYL beacause of stability, benzyl & ally
The equilibrium cell potential of the galvanic cell Pt | H 2 (g, f =1 bar) HCl (aq, 0.500mol kg -1 ) | Cl 2 (g, f =1 bar) | Pt is found to be E cell, eq = 1.410V at 298.15
475 ml at 54 psi to 1760 torr
Q. Write short note on units of hardness and their relationship. Sol. Units of hardness and their relationship. (1) Parts Per million (ppm): It is defined as t
Copper=54.1%, oxygen=20.1% and the balance sulfur. Could this also be the molecular formula? What other data is needed?
Characteristics?
decomposition of carbonates
how redox reaction influencing in everyday life
Zeroth law of thermodynamics
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