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Q. Show Equilibrium expression for water?
Ans.
The equilibrium expression for water is equal to a constant, Kw. This constant is called the ion product of water and is equal to 1.0 x 10-14:
Kw = [H+] [OH-] = 1.0 -> 10-14
There are two equilibrium constants, Ka and Kb, which are useful in describing the strength of acids and bases.
Suppose H-A and B-OH are an acid and base, respectively. Then Ka and Kb are defined as follows:
H-A -> H+ + A- Ka = [H+] [A-] / [H-A]
B-OH -> B+ + OH- Kb = [B+] [OH-] / [B-OH]
The higher Ka or Kb is, the greater the degree of ionization by the acid or base.
lithium and beryllium markedly differ from other members of their respective groups.
Q. Describe Peroxomonosulphuric Acid? It is also known as permonosulphuric acid. It is obtained by the action of chlorosulphuric acid on cold anhydrous hydrogen peroxide :
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What things i can include under this topic(reversible cell).
CAN I PLEASE GET A SALT ANALYSIS CHART FOR MY CHEMISTRY PRACTICALS?
write on blow moulding and thermoforming extensively. 3 pages
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dry air near sea level has the following composition by volume N2=78.08 percent,O2=20.94 percent. Calculate the partial pressure of each gas if atmospheric pressure is 1.00 atm
perkin ring clousre reaction
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