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Q. Show Crystal - Oscillator Circuits?
The simplest crystal-oscillator circuit is shown in Fig. 6-2A. An equivalent circuit is shown in Fig. 6-2B., where C4 represents the grid -cathode capacitance and C5 indicates the plate-cathode, or output capacitance. The ratio of these capacitors controls the excitation for the oscillator, and good practice generally requires that both of these capacitances be augmented by external capacitors, to provide better control of the excitation.
In the circuit shown below, the capacitor initially has a voltage across it 4 Volts (at t = 0). a. Write down the expression for V C (t) when the switch is closed. b. Writ
4GLs (Fourth Generations Languages) These are called non procedural languages May be considered as advanced HLL. Objects oriented programming languages and language with
Q. When input is a triangular wave. When the input fed to differentiating circuit is a triangular wave, the output will be a rectangular wave. During the period OA of
Q Using a combination of Uni-selectors and two motion selectors, draw a diagram of thousand line exchange and illustrate its working. Ans: The diagram for such an exchange i
Q. Explain Time-Dependent Circuit Analysis? The response of networks to time-varying sources is considered in this chapter. The special case of sinusoidal signals is of particu
A former employs a servant to look after his form house. He instructs the servant to keep a watch on his goat. So that he does not harm the kitchen garden, when the entrance-door
Application of vector impedance meter
Q. A person, while driving a car in a cyclone and waiting at an intersection, hears a thumping sound when a power line falls across the car and makes contact with the chassis. The
Q. What is Own-exchange routing? Distributed routing or own-exchange routing enables alternative routes to be chosen at intermediate nodes. Hence the strategy is capable of res
Write down basic postulates of sommerfield’s free electron gas model. Show that the number of energy states per unit energy is given by g(E) = 4Rv/h 3 (2m) 3/2 E 1/2 . What is
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