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Should I call a destructor explicitly on a local variable?
Aim: To implement a program to swap two numbers using reference arguments. Code: void swap(int *a, int *b) { int temp; temp=*a;
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A: They are following: Const: point out that memory once initialized, must not be modify through a program. Volatile: denote that value in the memory location can be modified
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Q: But MFC appear to encourage the employ of catch-by-pointer; should I do the similar? A: Depends. If you're utilizing MFC and catching one of their exceptions, by all means, d
Q: Should I call a destructor explicitly on a local variable? A: No. The destructor will get called again at close} of the block wherein the local was created. It is a guarantee of the language; it happens automatically; there''s no way to discontinue it from happening. But you can really get bad results from calling a destructor on the same object a second time! Bang! You''re dead!
Q: Should I call a destructor explicitly on a local variable?
A: No.
The destructor will get called again at close} of the block wherein the local was created. It is a guarantee of the language; it happens automatically; there''s no way to discontinue it from happening. But you can really get bad results from calling a destructor on the same object a second time! Bang! You''re dead!
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