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Shell sort - C Program:
Write a program to define shell sort.
void main()
{ //program for sorting by select sort
int a[20],i,k,j,n;
clrscr();
printf("How many nos are to be sorted\n");
scanf("%d",&n);
for (i=0;i<=n-1;i++)
{
printf("Enter the value of %d no\t",i+1);
scanf("%d",&a[i]);
}
printf("Make sure !Are your values read correctly?\n");
printf("%d \n",a[i]);
for (i=0;i<=n-1;i++) //In select sort we consider the 1 st element &
for (j=i+1;j<=n-1;j++) //compare it with the remaining in the 1st step
{ //&swaping is done next considering 2nd element etc.
if (a[i] >= a[j])
k=a[i];
a[i]=a[j];
a[j]=k;
printf("The sorted data is\n");
for (j=0;j<=n -1;j++)
printf("%d\n",a[j]);
getch();
The project is to design and write a C++11/FLTKgame program with a graphical user interface.The game is based on "pancake sorting," as described at http://en.wikipedia.org/wiki/P
simple coding for pebble merchant..
#I have assignment c with unix thread multiplication program ..
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can you help with the assignment, I don''t want to upload the assignment but want somebody to work with, do you do that?
A game is played with three piles of stones and two players. At her turn, a player removes one or more stones from the piles. However, if she takes stones from more than one pile,
#include void func(int num, b=5) { auto int total=0; static int sum=0; for ( int i=num; i>0 ; i--) total+=i; sum+=total; cout
Create a .cpp program that verifies the strength of a password that a user is entering is strong (complex/secure) enough. In the main area of the program, prompt the user to enter
Default Arguments A default argument is a value that is automatically assigned to a formal variable, if the actual argument from the function call is omitted. e.g. void
What if I wish a local to "die" before the close} of the scope wherein it was created? Can I call a destructor on a local if I want to?
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