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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
A simple mercury barometer Seal single end of a glass tube about 80 cm in length by rotating it in a gas flame. The tube should be held as almost vertical as possible. Join a s
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Monitoring of resource utilisation Continuous recording of the changes in the quality and quantity of various.resources is as imyortant an element of resource planning as ev
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What are Fatty acids Fatty acids are grouped into two classes, saturated and unsaturated fatty acids. The terms 'saturated' and 'unsaturated' fatty acid may not be new to yo
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