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For inequalities we contain a similar notation. Based on the complexity of the inequality the solution set might be a single number or it might be a range of numbers. If it is just one single number then we uses the same notation as we do for equations. If the solution set is a range of numbers, such as we looked at above is, we will use set builder notation. Following is the solution set for the inequality we looked at above.
{z | z ≥ -5}
It is read as : "The set of all z such that z is greater than or equal to -5".
Mostly inequalities that we will be looking at will have easy enough solution sets that we frequently just shorthand this as,
z ≥ -5
(3+2)^2+1-3^2.5
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det(adj A)for 1*1 matrix
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how to solve imaginary number such as like (-3v-5)² ?? Can I cancel the radical sign and the power of two ? and square the -3 and times to -5 ? hope you will answer this :) thanks
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