Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
In this case, the armature is connected in series with the field coils. Thus Ia = If = I
NB. At starting, the back emf is zero (because the motor is initially stationary) and hence the current is very large (limited only by the field and armature resistances). Hence the starting torque will be extremely large and if no load is applied (so that the torque requirement is small) the motor will accelerate rapidly to dangerously high speeds. A series connected motor must be started with a mechanical load attached to prevent the speed at start up rising to damaging speeds.Note that saturation of the magnetic material in the motor can occur at high currents and then the flux generated by the field coils becomes independent of current. This causes the characteristics to become similar to that of a shunt wound motor that also has an approximately constant field flux.
The series motor gives a high starting torque (proportional to 1/I2 ), 2.5 to 3 times the full load (rated) torque) but it falls rapidly as the speed increases. Applications: heavy duty, with intermittent starting under conditions where a mechanical load is always present - e.g. traction, cranes, hoists. etc
The speed of a series wound motor may be controlled by the addition of a resistor in parallel with the field coil. This divertssome of the current away from the field coil, reducing the field strength and hence the back emf at a given speed. The additional resistor is called a 'diverter'. The speed must increase to compensate this reduction in back emf. . Hence a reduction in the diverter resistance reduces the field strength and increases the speed of the motor.
A photodiode is made to detect light quickly a solar cell is made to collect energy from light. They are both typically silicon diodes, but modified to meet their dissimilar requir
Q. A three-phase balanced load draws 100 kW at 0.8 power factor lagging. In order to improve the supply power factor to 0.95 leading, a synchronous motor drawing 50 kWis connected
You should document each step of each iteration of your design. 1. You should include the following items from your preparation. a. A state diagram of the handshaking receive
Magnetic permeability and the B/H curve To measure the relationship between field strength H and flux density B for a material, a sample is made into a closed ring and a magne
circuit for the buck boost regulator connected to a ic regulator , my voltae range is 5v to 24v?
Explain Loads - Generation and Absorption of Reactive Power A load at 0.95 power factor implies a reactive power demand of 0.33 kVAr per kW of power. When planning a network, i
Q. A three-phase load, connected to a 440-V bus, draws 120 kWat a power factor of 0.85 lagging. In parallel with this load is a three-phase capacitor bank that is rated 50 kVAR . D
Saturation and Cutoff in bipolar junction transistor: Saturation : With both of the junctions forward-biased, a BJT is in saturation mode and makes easy high current condu
Transistor Switching Circuit Design a) Sketchy a schematic diagram showing how a transistor can be used to control the operation of a relay b) Determine what is meant by ba
what is 2 bit counter?
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd