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Semidifference via NOT IN and a subquery
SELECT StudentId
FROM IS_CALLED
WHERE Name = 'Devinder'
AND StudentId NOT IN (SELECT StudentId
FROM IS_ENROLLED_ON
WHERE CourseId = 'C1')
In above Example < > ALL replaces NOT IN and in the absence of NULL has the same effect. It reads, somewhat ambiguously, as "not equal to all". In fact the expression yields TRUE if and only if the condition comparing StudentId values is TRUE for every row in the result of the subquery.
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SELECT a.child_fname,a.child_lname,concat(b.parent_title,b.parent_fname), b.parent_lname,b.parent_tphone FROM child a,parent b WHERE a.parent_id=b.parent_id ORDER BY a.child_fnam
1- You can check attribute names from each table in DBF11 by running for example: desc dbf11.Member; desc dbf11.Agent; desc dbf11.Producer; Because some attribute names in
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a. Create a table odetails_new. It has all the attributes of odetails and an additional column called cost, whose values are the product of the quantity and price of the part bein
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